如何使用python查找文本文件的标准差？

Question

从我存储的游戏得分的文本文件中找到范围，最小值，最大值和平均值之后，我想从这些得分中找到标准偏差，但是我不确定该如何进行。

这是我到目前为止所拥有的：

file = open('stats.txt', 'a+')
file.write('\n' + 'Score: ' + str(1))
file.close()

numbers = []
with open('stats.txt') as fh:
    count = 0
    for line in fh:
        count += 1
        numbers.append(float(line.split()[1]))

file = open('maths.txt', 'w+')
file.write('Average Score: ' + str(sum(numbers)/len(numbers)) + "\n")
file.write('Maximum Score: ' + str(max(numbers)) + "\n")
file.write('Minimum Score: ' + str(min(numbers)) + "\n")
maxn = max(numbers)
minn = min(numbers)
rangex = (maxn) - (minn)
file.write('Range of Scores: ' + str(rangex))
file.close()

我的文本文件是什么样的：

Score: 3
Score: 0
Score: 13
Score: 13
Score: 9
Score: 0
Score: 0
Score: 0
Score: 0
Score: 0
Score: 0
Score: 31
Score: 0
Score: 0
Score: 0
Score: 0
Score: -8
Score: 0
Score: 0

感谢您的帮助

Answer 1

您只需要使用numpy的标准偏差函数即可。

添加到代码的开头：

supplied_username = input("Please enter your name. ")
print("Your username has been created and is", supplied_username)
supplied_password = input("Now please create a password. ")
file = open("Login.txt","a")
file.write (supplied_username)
file.write (",")
file.write (supplied_password)
file.write("\n")
file.close()

logged_in = False
with open('Login.txt', 'r') as file:
    for line in file:
        supplied_username, supplied_password = line.split(',')
username = input("please enter your username")
if username == supplied_username:
    password = input("please enter your password")
if password == supplied_password:
    logged_in = True
    break

if logged_in:
    print("welcome!")
else:
    ("please, register an account")

然后使用：

import numpy as np

Answer 2

您可以读取文件并在:上拆分以创建列表：

l = []

In [400]: with open('stats.txt', 'r') as f:
     ...:     for i in f:
     ...:         l.append(int(i.split(':')[1].strip()))


In [401]: l
Out[401]: [3, 0, 13, 13, 9, 0, 0, 0, 0, 0, 0, 31, 0, 0, 0, 0, -8, 0, 0]

In [403]: import statistics
In [402]: statistics.stdev(l)
Out[402]: 8.357158922932953

或者您也可以使用numpy：

In [404]: import numpy as np
In [403]: np.std(l)
Out[403]: 8.1342611825629