多次闯入和闯入计算sql-server

时间：2018-11-20 07:51:13

标签： sql sql-server tsql

您好，我想按日期计算“多次进出时间”组。

下面是当前表数据

userid  checktime
2336    2018-11-01 08:28:20.000
2336    2018-11-01 13:27:18.000
2336    2018-11-01 13:31:12.000
2336    2018-11-01 18:03:57.000
2336    2018-11-04 07:59:09.000
2336    2018-11-04 13:10:58.000
2336    2018-11-04 13:17:46.000
2336    2018-11-04 17:58:03.000
2336    2018-11-05 08:08:07.000
2336    2018-11-05 13:10:13.000
2336    2018-11-05 13:14:12.000
2336    2018-11-05 17:58:58.000
2336    2018-11-05 17:59:02.000
2336    2018-11-06 07:40:51.000
2336    2018-11-06 13:09:48.000
2336    2018-11-06 13:14:30.000
2336    2018-11-06 17:55:07.000
2336    2018-11-07 07:53:18.000
2336    2018-11-07 13:49:19.000
2336    2018-11-07 13:53:16.000
2336    2018-11-07 18:02:12.000
2336    2018-11-08 07:45:14.000
2336    2018-11-08 13:18:28.000
2336    2018-11-08 13:21:59.000
2336    2018-11-08 18:00:04.000

查询的预期结果

UserID  Date       timein1 timeout1 timein2 timeout2 timein3 timeout3
2336    1-Nov-18    8:28    13:27   13:31   18:03       
2336    4-Nov-18    7:59    13:10   13:17   17:58       
2336    5-Nov-18    8:08    13:10   13:14   17:58     17:59

借助戈登逻辑创建的查询

`DECLARE @EMPID AS VARCHAR(50) = '101356'
DECLARE @CHECKTIME AS DATE ='11-01-2018'
DECLARE @CHECKTIME2 AS DATE = '11-20-2018'
select convert(varchar,checkdate,6) as DAYDATE,
       DAYPART,
       CASE WHEN DATEDIFF(MINUTE,(MIN(thetime)),(MAX(thetime))) = 0 AND (DATEDIFF(MINUTE,'08:45:00',(CONVERT(VARCHAR(20), MIN(thetime), 108)))) > 240 OR (DATEDIFF(MINUTE,'08:45:00',(CONVERT(VARCHAR(20), MIN(thetime), 108)))) < 0 THEN ' '
       ELSE (DATEDIFF(MINUTE,'08:30:00',(CONVERT(VARCHAR(20), MIN(thetime), 108)))) END AS LATETIMEIN,
       CASE WHEN DATEDIFF(MINUTE,(MIN(thetime)),(MAX(thetime))) = 0 AND (DATEDIFF(MINUTE,'08:30:00',(CONVERT(VARCHAR(20), MIN(thetime), 108)))) > 240 THEN ' '
       ELSE CONVERT(VARCHAR(20), MIN(thetime), 108) END AS TIMEIN2,
       max(case when seqnum = 2 then thetime  end) as BreakOut1,
       max(case when seqnum = 3 then thetime end) as BreakIn1,
       CASE WHEN DATEDIFF(MINUTE,(MIN(thetime)),(MAX(thetime))) = 0 AND (DATEDIFF(MINUTE,(CONVERT(VARCHAR(20), MAX(thetime), 108)),'18:00:00')) > 240 THEN ' '
       ELSE CONVERT(VARCHAR(20), MAX(thetime), 108) END AS TIMEOUT2,       
       CASE WHEN DATEDIFF(MINUTE,(MIN(thetime)),(MAX(thetime))) = 0 AND (DATEDIFF(MINUTE,(CONVERT(VARCHAR(20), MAX(thetime), 108)),'18:00:00')) > 240 OR (DATEDIFF(MINUTE,(CONVERT(VARCHAR(20), MAX(thetime), 108)),'18:00:00')) < 0 THEN ' '
       ELSE (DATEDIFF(MINUTE,(CONVERT(VARCHAR(20), MAX(thetime), 108)),'18:00:00')) END AS EARLYTIMEOUT,
       (convert(varchar(30), (datediff(mi, (MIN(thetime)), (MAX(thetime))) / 60)) + ':' + convert(varchar(30), (datediff(mi, (MIN(thetime)), (MAX(thetime))) % 60))) As WORKhrs,
       DATEDIFF(mi,(MIN(thetime)),(MAX(thetime))) as WRSMIN,
       Remarks
from 
(select 
       convert(date,d.Caldate) as checkdate,
       SUBSTRING(DATENAME(DW,CONVERT(VARCHAR(20),D.Caldate,106)),1,3) AS DAYPART,
       cast(convert(varchar(20),c.checktime,108)as varchar) as thetime,
       D.Holiday as Remarks,
       row_number() over (partition by c.userid, convert(date, c.checktime) order by c.checktime) as seqnum
       FROM Calender AS D
       CROSS JOIN USERINFO AS E
       LEFT OUTER JOIN CHECKINOUT AS C ON (E.USERID = C.USERID AND CONVERT(VARCHAR,C.CHECKTIME,5)=CONVERT(VARCHAR,D.CALDATE,5) )
       RIGHT JOIN Employee AS X ON E.BADGENUMBER=X.EmployeeID OR E.BADGENUMBER=X.Badgenumber
       WHERE X.EmployeeID=@EMPID AND D.Caldate >= @CHECKTIME AND D.Caldate <= @CHECKTIME2
     ) t
group by checkdate,DAYPART,Remarks`

输出为

DAYDATE DAYPART LATETIMEIN TIMEIN2 BreakOut1 BreakIn1 TIMEOUT2 EARLYTIMEOUT WORKhrs WRSMIN备注 18年11月1日星期四24 08:54:59 17:27:30空17:27:30 33 8:33 513空 18 Nov 02 Fri NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL 18年11月3日，星期六NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL 2018年11月4日星期日18 08:48:43 NULL NULL 0 0：0 0 NULL 05 Nov 18 Mon 21 08:51:45 18:23:19 NULL 18:23:19 0 9:32 572 NULL 2018年11月6日星期二19：08：49：45 18:27:15空18:27:15 0 9:38 578空 2018年11月7日星期三28 08:58:16 18:21:30空18:21:30 0 9:23 563空 18年11月8日星期四0 08:42:52 18:13:03空18:13:03 0 9:31 571空 18年11月9日星期五NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL 2018年11月10日星期六NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL 18年11月11日，星期日48 09:18:30 19:01:48空19:01:48 0 9:43 583空 11 Nov 12 Mon 0 08:38:51 18:24:08 NULL 18:24:08 0 9:46 586 NULL 18 Nov 13 Tue 0 08:35:27 18:02:17 20:07:09 20:07:09 0 11:32 692 NULL 18 Nov 14周三30 09:00:54 18:12:38空18:12:38 0 9:12 552空 18年11月15日星期四0 08:08:50 18:29:32空18:29:32 0 10:21 621空 2018年11月16日星期五NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL 18年11月17日星期六NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL 18 Nov 18周日NULL NULL NULL NULL NULL NULL NULL NULL NULL先知穆罕默德（PBUH）的生日 19 Nov 18 Mon 23 08:53:35 18:08:07 NULL 18:08:07 0 9:15 555 NULL 18 Nov 20 Tue 29 08:59:02 18:47:33 NULL 18:47:33 0 9:48 588 NULL

2 个答案:

答案 0 :(得分：0)

您可以根据需要使用PIVOT。此外，似乎您每天的时间都是特定的。因此，您需要动态查找时间列名称。我已经根据您的需求准备了一些查询，您可以使用它：

DROP TABLE #UserCheck
CREATE TABLE #UserCheck
(
    userid      INT
    ,checktime  DATETIME
)
INSERT INTO #UserCheck
VALUES
(2336,'2018-11-01 08:28:20.000')
,(2336,'2018-11-01 13:27:18.000')
,(2336,'2018-11-01 13:31:12.000')
,(2336,'2018-11-01 18:03:57.000')
,(2336,'2018-11-04 07:59:09.000')
,(2336,'2018-11-04 13:10:58.000')
,(2336,'2018-11-04 13:17:46.000')
,(2336,'2018-11-04 17:58:03.000')
,(2336,'2018-11-05 08:08:07.000')
,(2336,'2018-11-05 13:10:13.000')
,(2336,'2018-11-05 13:14:12.000')
,(2336,'2018-11-05 17:58:58.000')
,(2336,'2018-11-05 17:59:02.000')
,(2336,'2018-11-06 07:40:51.000')
,(2336,'2018-11-06 13:09:48.000')
,(2336,'2018-11-06 13:14:30.000')
,(2336,'2018-11-06 17:55:07.000')
,(2336,'2018-11-07 07:53:18.000')
,(2336,'2018-11-07 13:49:19.000')
,(2336,'2018-11-07 13:53:16.000')
,(2336,'2018-11-07 18:02:12.000')
,(2336,'2018-11-08 07:45:14.000')
,(2336,'2018-11-08 13:18:28.000')
,(2336,'2018-11-08 13:21:59.000')
,(2336,'2018-11-08 18:00:04.000');

drop table #temp; 
SELECT  userid
        ,cast(checktime as date) [CheckDate]
        ,'timein'+CAST(ROW_NUMBER() OVER(PARTITION BY userid,cast(checktime as date) ORDER BY userid,cast(checktime as date)) AS varchar) AS Seq
        ,cast(checktime as time)  [CheckTime] 
INTO #Temp
FROM #UserCheck

DECLARE @DynamicColumns VARCHAR (MAX)
DECLARE @SQLString      VARCHAR (MAX)

   SET @DynamicColumns=STUFF((SELECT distinct ',' + QUOTENAME(Seq) 
                    from  #Temp  
            FOR XML PATH(''), TYPE
            ).value('.', 'NVARCHAR(MAX)') 
        ,1,1,'');


SET @SQLString='
SELECT * 
FROM 
    (   SELECT * 
        FROM #Temp
    ) Temp
    PIVOT 
        (
            MAX(CheckTime)
            FOR Seq in ('+@DynamicColumns+')
        ) P'

EXEC(@SQLString)

答案 1 :(得分：0)

如果最多有三对列，则可以使用条件聚合：

select userid, checkdate,
       max(case when seqnum = 1 then thetime end) as timein1,
       max(case when seqnum = 2 then thetime end) as timeout1,
       max(case when seqnum = 3 then thetime end) as timein2,
       max(case when seqnum = 4 then thetime end) as timeout2,
       max(case when seqnum = 5 then thetime end) as timein3,
       max(case when seqnum = 6 then thetime end) as timeout3
from (select t.*,
             convert(date, checktime) as checkdate,
             cast(checktime as time) as thetime,
             row_number() over (partition by userid, convert(date, checktime) order by checktime) as seqnum
      from t
     ) t
group by userid, checkdate
order by userid, checkdate;
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