Question

这是我的表格数据

        id EVENTID       DT
        1   1   2018-06-21 16:00:00.000
        1   4   2018-06-21 14:00:00.000
        1   3   2018-06-21 13:00:00.000
        1   4   2018-06-21 11:00:00.000
        1   3   2018-06-21 10:00:00.000
        1   0   2018-06-21 08:17:12.000

Eventid： 0 in 1出 3作为突破 4作为闯入

我使用过以下查询，但无法在同一行中获取所有中断时间

select
    t.emp_reader_id as empId,B.emp_name, cast(max(DT) as date) as Belongs_to,B.areaname as POINTID, max(iif(EVENTID = 0, DT, null)) as EntryTime, max(iif(EVENTID = 1, DT, null)) as ExitTime,
     max(iif(EVENTID = 3, DT, null)) as Breakin, max(iif(EVENTID = 4, DT, null)) as Breakout,
      format(dateadd(ss,Datediff(second,max(iif(EVENTID = 0, DT, null)),max(iif(EVENTID = 1, DT, null))),0),'HH:mm') as Worked
      ,CONVERT( CHAR(11), @Date_From, 103 ) as StartDate
      ,CONVERT( CHAR(11), @Date_To, 103 ) as ToDate
from (  
    select
        *, grp =sum(iif(EVENTID = 1,0, 0) ) over (partition by emp_reader_id order by DT) ,
        grp1 =   sum(iif(EVENTID = 3,4, 0) )over (partition by emp_reader_id order by DT)
    from
        Trnevents
) t inner join employee B on t.emp_reader_id=B.emp_reader_id
   group by t.emp_reader_id,t.grp,B.emp_name,t.Belongs_to,B.areaname

预期输出：

  empId emp_name    Belongs_to  POINTID        EntryTime          ExitTime        Breakout1             Breakout1             Breakout2         Breakout2  Worked     StartDate     ToDate
    1         ***      2018-06-21     ***   2018-06-21 08:17:12     2018-06-21 16:00:00 2018-06-21 11:00:00 2018-06-21 13:00:00 2018-06-21 13:00:00 2018-06-21 14:00:00 05:42   2018-06-21  2018-06-21

预先感谢

Answer 1

正如您所建议的那样，突破次数有限，只要按照顺序进行就可以了，直到最后。

我以某种方式看待这个问题，如果多个id的中断次数不同，那么它可能会导致您进入动态sql。

SELECT id AS empid, convert(varchar , stbstr(tt, 1, 10) , 2) AS Belongs_to, 
convert(varchar ,stbstr(TT, instr(TT, '$1', 1), instr(TT, '$1', 1)+23) , 2) AS EntryTime,...
FROM (
SELECT id, string_agg(dt + '$' + cast(EventID AS VARCHAR) + DT , ',') AS TT
FROM time_table
GROUP BY id
)

如何获得进入和退出时间SQL？

1 个答案: