Question

我现在正在制作一个动态表格，复制表格很容易，但是有一个文本字段，其值来自数据库，问题是，数据库值无法重复。关键是我试图在php中复制一个值，这就是问题所在，是否有使用<label>将数据插入数据库的问题？因为使用<label>复制值是成功的

这是我的代码。

<?php
include 'config/db_connect.php';

if(isset($_POST['submit'])){
for($i = 0; $i <= count($_POST['kode'])-1;$i++){
$selectidmax =mysqli_query($con, "SELECT max(jenis) as maxjenis FROM t_produk WHERE jenis LIKE 'SS%'");
$hslidmax=mysqli_fetch_array($selectidmax);
$idmax=$hslidmax['maxjenis'];
$nourut = (int) substr($idmax, 2,3);
$nourut++;
$IDbaru = "SS" . sprintf("%03s", $nourut);
$kodep = $_POST['kode'][$i];
$kodeproduk = $_POST['kp'][$i];
$produk = $_POST['produk'][$i];
$bunga = $_POST['bunga'][$i];
$ket = $_POST['ket'][$i];

$query = mysqli_query($con, "INSERT INTO t_produk(kode_cu,jenis,kode_produk,produk,bunga,keterangan)
    VALUES (
    '$kodep',
    '$IDbaru',
    '$kodeproduk',
    '$produk',
    '$bunga',
    '$ket') 
    ");
}

    if($query){
        header("location:home_cu.php");
    }else{
        echo "gagal" . mysqli_error($con);
    }
}
?>
<!DOCTYPE html>
<html>
<head>
    <title>Form Simpanan Saham</title>
<link rel="stylesheet" href="https://www.w3schools.com/w3css/4/w3.css">
<link rel="stylesheet" type="text/css" href="css/style.css">
<link rel="stylesheet" type="text/css" href="css/style1.css">
<link rel="stylesheet" type="text/css" href="css/bootstrap.css">
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/4.1.3/css/bootstrap.min.css">
<script src="https://cdnjs.cloudflare.com/ajax/libs/popper.js/1.14.3/umd/popper.min.js"></script>
<script src="https://maxcdn.bootstrapcdn.com/bootstrap/4.1.3/js/bootstrap.min.js"></script>
</head>
<body>
<div class="w3-bar w3-black">
  <a href="home_cu.php" class="w3-bar-item w3-button">Home</a>
  <a href="view_cu.php" class="w3-bar-item w3-button">Menu Data Cu</a>
  <a href="home_kebijakan.php" class="w3-bar-item w3-button">Menu Data Kebijakan</a>
  <a href="data_modifikasi.php" class="w3-bar-item w3-button">Menu Data Modifikasi</a>
</div>
<br>
<div class="container">
        <form action="form_saham.php" method="post">
                <h1 class="text-center">Produk Pinjaman</h1>
                <div class="form-content">
                <div class="row">
                    <div class="col-md-12">
                        <p><button type="button" id="btnAdd" class="btn btn-primary">Add More</button></p>
                        <br/>
                    </div>
                </div>
                <div class="row group">
                    <div class="col-md-3">
                        <div class="form-group">
                        <?php 
include 'config/db_connect.php';
$kode = $_GET['kode_cu'];
$query = mysqli_query($con,"SELECT * FROM t_cu WHERE kode_cu = '$kode'");
while ($hasil = mysqli_fetch_array($query) ) {
?>
                            <label>Kode Produk :</label>
                            <input type="text" value="<?php echo $hasil['kode_cu']?>" name="kode[]" class="form-control">
                            <input type="text" name="kp[]" class="form-control"/>
                        </div>
                    </div>
                    <div class="col-md-3">
                        <div class="form-group">
                            <label>Produk</label>
                            <input type="text" name="produk[]" class="form-control">
                        </div>
                    </div>
                    <div class="col-md-4">
                        <div class="form-group">
                            <label>Bunga</label>
                            <input type="text" name="bunga[]" class="form-control">
                        </div>
                    </div>
                    <div class="col-md-5">
                        <div class="form-group">
                            <label>Keterangan</label>
                            <textarea name="ket[]" class="form-control" rows="3"></textarea>
                        </div>
                    </div>
                    <div class="col-md-2">
                        <div class="form-group">
                            <button type="button" class="btn btn-danger btnRemove">Remove</button>
                        </div>
                    </div>
                </div>
            </div>
            <button type="submit" name="submit" class="btn btn-primary">Submit</button>
        </form>
    </div>
    <?php } ?>
<script src="assets/js/jquery.min.js"></script>
    <!-- Include all compiled plugins (below), or include individual files as needed -->
    <script src="assets/js/bootstrap.min.js"></script>
    <script src="jquery.multifield.min.js"></script>
    <script>
        $('.form-content').multifield({
            section: '.group',
            btnAdd:'#btnAdd',
            btnRemove:'.btnRemove',
        });
    </script>
</body>
</html>

Answer 1

好吧，我自己找到了一个问题，我只是将<input type="text" value="<?php echo $hasil['kode_cu']?>" name="kode[]" class="form-control">移到了顶部，所以该文本字段不会重复，然后在数据库值中将'$kodep',更改为{ {1}}感谢所有尝试提供帮助的人

无法从PHP上的数据库中复制值

1 个答案: