我试图从数据库行中获取单个值,但无论我使用什么,我什么也得不到。我试过了
$con=mysqli_connect("localhost","user","pass","db");
$product_cat = mysql_result(mysqli_query($con,"SELECT product_category_id FROM am_product_product_category WHERE product_id=1 limit 1"),0);
和
$product_cat = mysql_fetch_assoc(mysqli_query($con,"SELECT product_category_id FROM am_product_product_category WHERE product_id=1 limit 1"));
和
$product_cat = mysqli_fetch_field(mysqli_query($con,"SELECT product_category_id FROM am_product_product_category WHERE product_id=1 limit 1"));
和
$product_cat = mysql_fetch_object(mysqli_query($con,"SELECT product_category_id FROM am_product_product_category WHERE product_id=1 limit 1"));
和
$product_cat = mysql_fetch_row(mysqli_query($con,"SELECT product_category_id FROM am_product_product_category WHERE product_id=1"));
但是当我回显$ product_cat时我什么也得不到(它应该回应1)。你能告诉我我做错了吗?
谢谢。
答案 0 :(得分:0)
因为你正在混合mysqli_ *和mysql_ *函数,只能使用mysqli_ *函数
试试这个:
$product_cat = mysqli_fetch_row(mysqli_query($con,"SELECT product_category_id FROM am_product_product_category WHERE product_id=1"));
echo $product_cat['product_category_id'];
print_r($product_cat);
答案 1 :(得分:0)
你的sql查询是否正确?
首先检查它,然后使用mysqli_fetch_row
重试。
如果您还遇到问题,可以尝试使用mysqli_fetch_array
,然后使用$result[0]
这个字段。
否则,您可以使用print_r($result)
打印结果以检查问题。
答案 2 :(得分:0)
试试这个
$product_cat = mysqli_query($con,"SELECT product_category_id FROM am_product_product_category WHERE product_id=1 limit 1");
$row=mysqli_fetch_assoc($product_cat);
echo $row["product_category_id"] ;
如果您要获取许多值,请使用以下命令:
$product_cat = mysqli_query($con,"SELECT product_category_id FROM am_product_product_category WHERE product_id=1 limit 1");
while ($row=mysqli_fetch_assoc($product_cat)){
echo $row["product_category_id"] ."<br />";
}
答案 3 :(得分:0)
请按照此示例。我认为此示例对您有所帮助。
$id = $_GET['id'];
$result = mysqli_query($con,"select *from employee_details where emp_id= '$id' ");
echo "Emp-Id";
$row = mysqli_fetch_array($result)
echo ". $row['emp_id'] . ";
mysqli_close($con);
(or)
也尝试这个
$product_cat = $mysqli->query("SELECT product_category_id FROM am_product_product_category WHERE product_id=1")->fetch_object()->product_category_id;
使用此代码。
答案 4 :(得分:0)
这是Programmer999提供的正确答案:
$product_cat = $con->query("SELECT product_category_id FROM am_product_product_category WHERE product_id=1")->fetch_object()->product_category_id;