Question

我有一个简单的注册脚本，但是android studio无法正确将数据放入php脚本中。我在浏览器上运行了php脚本，它可以很好地放置数据，但是android studio却做得不好。

这是注册请求脚本。

public class RegisterRequest extends StringRequest {

    private static final String REGISTER_REQUEST_URL = "http://192.168.*.*:80/phptesting/Register.php";
    private Map<String, String> params;
    public RegisterRequest(String username, String password,String isAdmin,
                           Response.Listener<String> listener,
                           Response.ErrorListener errListener){
        super(Method.POST, REGISTER_REQUEST_URL,listener,errListener);
        params = new HashMap<>();
        params.put("username",username);
        params.put("password",password);
        params.put("isAdmin",isAdmin+"");
    }

    public Map<String, String> getparams() {
        return params;
    }
}

这是创建用户脚本

public class CreateUser extends AppCompatActivity {
    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_create_user);
        this.setTitle("Create User");
        final EditText username1 = findViewById(R.id.Createusername);
        final EditText password1 = findViewById(R.id.CreatePassword);
        final Switch isAdmin = findViewById(R.id.isadmin);
        final Button createuser = findViewById(R.id.createuserbtn);
        if (getIntent().hasExtra("com.example.northlandcaps.crisis_response")){
            isAdmin.setVisibility(View.GONE);
        }
        createuser.setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View v) {
                final String username = username1.getText().toString();
                final String password = password1.getText().toString();
                final String isadmin = isAdmin.getText().toString();
                Response.Listener<String> responseListener = new Response.Listener<String>() {
                    @Override
                    public void onResponse(String response) {
                        Log.d("Response Value: ", response);
                            if (response.equals("success")){
                                Intent intent = new Intent(CreateUser.this, MainActivity.class);
                                CreateUser.this.startActivity(intent);
                            }else{
                                AlertDialog.Builder builder = new AlertDialog.Builder(CreateUser.this);
                                builder.setMessage("Register Failed")
                                        .setNegativeButton("Retry",null)
                                        .create()
                                        .show();
                        }
                    }
                };Response.ErrorListener errorListener = new Response.ErrorListener() {
                    @Override
                    public void onErrorResponse(VolleyError error) {
                        Toast.makeText(getApplicationContext(), String.valueOf(error), Toast.LENGTH_SHORT).show();
                    }
                };
                RegisterRequest registerRequest = new RegisterRequest(username,password,isadmin,responseListener,errorListener);
                RequestQueue queue = Volley.newRequestQueue(CreateUser.this);
                queue.add(registerRequest);
            }
        });

    }

这是php脚本

<?php
    $db_host = '192.168.*.*:3306';
    $db_user = 'root';
    $db_pass = '';
    $db_name = 'test';
    var_dump($_POST["username"]);//line 6
    $con = mysqli_connect($db_host,'root',$db_pass,$db_name);
    if($con){
        echo "connection successful";
    }
    if (mysqli_connect_errno()) {
    printf("Connect failed: %s\n", mysqli_connect_error());
    exit();
    }
    if(isset($_POST["isAdmin"]) &&  isset($_POST["username"]) && isset($_POST["password"]))
{
    $username = $_POST["username"];
    $password = $_POST["password"];
    $isAdmin = $_POST["isAdmin"];

    $statement = mysqli_prepare($con, "INSERT INTO cresidentials (username,password,isAdmin) VALUES (?, ?, ?)");
    mysqli_stmt_bind_param($statement,'ssi',$username,$password,$isAdmin);
    mysqli_stmt_execute($statement);

    if(!$statement) 
    {
         printf("Prepare failed: %s\n", mysqli_error($con)); 
    }

    echo "success";
}
else
 echo "values not set";
?>

运行此命令时，应用程序会创建重试错误弹出消息。输出是这个；

注意：未定义索引：第6行的C：\ xampp \ htdocs \ phptesting \ Register.php中的用户名未设置NULL连接成功值

我相信它抱怨用户名没有任何意义。这是一个很大的问题，因为其他变量在下面定义，并且我不知道它们是否通过了脚本是否提前停止了？感谢所有帮助，谢谢

Answer 1

尝试在php文件中获取像这样的json

$json = json_decode(file_get_contents('php://input'), true);

Android Studio无法与$ _POST通信

1 个答案: