如何将两个字节的整数添加到数组？

Question

我需要将整数转换为2个字节（0 x ...），该怎么做？

int port = 7777;
byte[] bufferPost = { 0xBC, 0x5F, ..., 0xbyte1OfIntValue, 0xbyte2OfIntValue }; 

Answer 1

类似这样的东西：

  byte[] bufferPost = new byte[] {
    0x12, 0x23, 0x45};

  int port = 7777;

  Array.Resize(ref bufferPost, bufferPost.Length + 2);

  bufferPost[bufferPost.Length - 2] = (byte)(port & 0xFF);
  bufferPost[bufferPost.Length - 1] = (byte)((port >> 8) & 0xFF);

  // Let's have a look what's going on
  Console.Write(string.Join(" ", bufferPost.Select(item => "0x" + item.ToString("x2"))));

结果：

  0x12 0x23 0x45 0x61 0x1e

Answer 2

这不是最好的解决方案，但它可行

int port=7777;
string temp=Convert.ToString(port);
int firstbyte=Convert.ToInt32(temp.SubString(0,2));
int secondbyte=Convert.ToInt32(temp.Substring(2));
byte b1=(byte)firstbyte;
byte b2=(byte)secondbyte;