Question

我正在尝试使用Observable.zip对api进行并行调用。这些api调用中的每一个都返回一个Observable>。我正在创建一个Observable列表，并将该列表与返回由这些api调用返回的单个Observable>组成的Observable>函数一起发送至zip。出于某些原因，object []可以用20个TreeSet项初始化，这很好，但是每个TreeSet为空，尽管在日志中我可以发现api调用包含数据的响应。

subscription = repository
            .getFollowers(id, OFFSET)
            .subscribeOn(Schedulers.io())
            .map(FollowerResponse::getCollection)
            .flatMap((Function<List<Follower>, Observable<TreeSet<Track>>>) followers -> {
                List<Observable<TreeSet<Track>>> list = new ArrayList<>();
                observable = repository.getTracks(OFFSET, String.valueOf(followers.get(0).getId()));
                list.add(observable.subscribeOn(Schedulers.io())
                        .onErrorResumeNext(Observable.empty()));
                for (int i = 1; i < followers.size(); i++) {
                    observable = Observable.merge(observable, repository.getTracks(OFFSET, String.valueOf(followers.get(i).getId())));

                    list.add(observable.subscribeOn(Schedulers.io())
                            .onErrorResumeNext(Observable.empty()));
                }

                return Observable.zip(list, new Function<Object[], TreeSet<Track>>() {
                    @Override
                    public TreeSet<Track> apply(Object[] objects) throws Exception {
                        TreeSet<Track> treeSet = new TreeSet<>();
                        Log.e("zip ", "inside zip");
                        for (Object obj : objects) {
                            treeSet.addAll((TreeSet<Track>) obj);
                        }
                        return treeSet;
                    }

                });
            })
            .observeOn(AndroidSchedulers.mainThread())
            .subscribe(new Consumer<TreeSet<Track>>() {
                @Override
                public void accept(TreeSet<Track> tracks) throws Exception {
                    Log.e("zip ", "inside subscribe");
                }
            });

Answer 1

该死，我只是意识到我没有删除在Observable.zip之前尝试使用的Observable.merge！确实有帮助发布，就像在想一声大声笑

RxJava zip合并api调用

1 个答案: