Question

我当前的Android应用程序使用Retrofit和RxJava来编排我的网络呼叫。

我将HTTP GET建模为Single<Response<String>>，将POST建模为Completable。

我需要的呼叫顺序如下：-

依次调用GET（1），GET（2），GET（3）

并行调用POST（1），POST（2）

当POST（1）和POST（2）都完成OK后，请调用GET（4）。

我有部分解决方案。我已经编码了前三个GET的调用然后是POST调用

我的代码类似于：-

Single.concat(getRequests())
                .subscribeOn(Schedulers.single())
                .doOnError(throwable -> Log.e(TAG, "Manage Totals Failed", throwable))
                .doFinally(new Action() {
                    @Override
                    public void run() throws Exception {
                        manageExecutions(combineExecutions());
                    }
                })
                .subscribe();

    /**
     * @return
     */
    private static Iterable<Single<Response<String>>> getRequests() {
        final API_CALL_GET[] apiCalls = API_CALL_GET.values();
        final List<Single<Response<String>>> requests = new ArrayList<>(apiCalls.length);

        for (final API_CALL_GET apiCall : apiCalls) {
            requests.add(apiCall.request());
        }

        return requests;
    }

public enum API_CALL_GET {

    GET_ONE {
        @Override
        public Single<Response<String>> request() {
            return RETRO_SERVICE
                .getOne(authToken, new HashMap<>())
                .doAfterSuccess(this::persistDataOne)
                .doOnError(error -> ever(error));
        }
    }, GET_TWO {
        @Override
        public Single<Response<String>> request() {
            return RETRO_SERVICE
                .getTwo(authToken, new HashMap<>())
                .doAfterSuccess(this::persistDataTwo)
                .doOnError(error -> ever(error));
        }
    },
    GET_THREE {
        @Override
        public Single<Response<String>> request() {
            return RETRO_SERVICE
                .getThree(authToken, new HashMap<>())
                .doAfterSuccess(this::persistDataThree)
                .doOnError(error -> ever(error));
        }
    };

    public abstract Single<Response<String>> request();

}


    private static Action manageExecutions(final List<Completable> completables) {

        return new Action() {
            @Override
            public void run() throws Exception {
                Completable
                .concat(completables)
                .subscribeOn(Schedulers.io())
                .doOnError(throwable -> Log.e(TAG, "Manage Totals Failed", throwable))
                .doOnComplete(new Action() {
                    @Override
                    public void run() throws Exception {
                        accumulateAmounts();
                    }
                })
                .subscribe();
            }
        };
    }


    /**
     * @return
     */
    private static List<Completable> combineExecutions() {
        final API_CALL_POST[] apiCalls = API_CALL_POST.values();
        final List<Completable> requests = new ArrayList<>(apiCalls.length);

        for (final API_CALL_POST apiCall : apiCalls) {
            requests.addAll(apiCall.requests());
        }

        return Lists.newArrayList(Iterables.unmodifiableIterable(requests));
    }

public enum API_CALL_POST {

    POST_ONE {
        @Override
        public List<Completable> requests() {
            return NetworkController.postRecommenderExecutions();
        }
    },
    POST_TWO {
        @Override
        public List<Completable> requests() {
            return NetworkController.postSavedSearcheExecutions();
        }
    };

    public abstract List<Completable> requests();

}


    public static List<Completable> postONE() {
        final List<Completable> completables = new ArrayList<>();

        final List<OneDO> oneDOS = fetchOnes();

        for (final OneDO oneDO : oneDOS) {
            completables.add(RETRO_SERVICE.runCompletableOnes(authToken, oneDO.getId())
                    .doOnError(new Consumer<Throwable>() {
                        @Override
                        public void accept(final Throwable throwable) throws Exception {
                            Log.e(TAG, "accept: ", throwable);
                        }
                    }));
        }

        return completables;
    }




    public static List<Completable> postTWO() {
        final List<Completable> completables = new ArrayList<>();

        final List<TwoDO> twoDOS = fetchTwos();

        for (final TwoDO twoDO : twoDOS) {
            completables.add(RETRO_SERVICE.runCompletableTwos(authToken, twoDO.getId())
                    .doOnError(new Consumer<Throwable>() {
                        @Override
                        public void accept(final Throwable throwable) throws Exception {
                            Log.e(TAG, "accept: ", throwable);
                        }
                    }));
        }

        return completables;
    }

我遇到的困难是正确地链接了我的电话

例如我以为我可以开发出类似于此伪代码的解决方案

Single.concat（GET_1 ... GET_N）.onComplete（POST_1 ... POST_N）.onComplete（GET_LAST）

但是，我当前的部分解决方案仅调用第一组GET，然后调用POST，并且GET和POST调用未“链接”

我看不到如何创建支持我的用例的呼叫链。

是否可以在链接的呼叫中组合Single-> Completable-> Single？

更新

基于Daniil的答案，我最终得到了以下解决方案：-

 Single.concat(getRequests())
                .subscribeOn(Schedulers.io())
                .doOnError(throwable -> Log.e(TAG, "accept[0000]: ", throwable))
                .ignoreElements()
                .andThen(Completable.merge(combineExecutions()))
                .doOnError(throwable -> Log.e(TAG, "accept: ", throwable))
                .doOnComplete(() -> Controller.accumulateTotals())
                .subscribe();

Answer 1

在科特林，它看起来像这样：

fun generateGetRequests(): List<Single<Response<String>>> {
    return listOf(retrofit.firstGet(), retrofit.secondGet(), ... ,retrofit.lastGet())
}

fun generatePostRequests(): List<Completable> {
    return listOf(retrofit.firstPost(), ..., retrofit.lastPost())
}

fun doSomethingWithResponses(responses: Array<Any>) {
    // Do Something, like save to db
}

fun runRequests() {
    Single.zip(generateGetRequests(), { responses ->
        doSomethingWithResponses(responses)
    }).ignoreElements()
        .andThen(Completable.merge(generatePostRequests()))
        .subscribeOn(Schedulers.io())
        .subscribe()
}

Answer 2

通过将不同的类型转换为共享的反应类型（例如Observable）并进行串联，或者通过flatMapX和{{1 }}：

andThen

如何在Android应用程序中结合RxJava单个和可完成的改造调用

2 个答案: