我正在使用媒体信息,以获取有关电影的一些xml信息:
mediainfo --Output=XML Krtek\ a\ buldozer-jdvwqZUEbhc.mkv | xmlstarlet format
输出为:
<?xml version="1.0" encoding="UTF-8"?>
<MediaInfo xmlns="https://mediaarea.net/mediainfo" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="https://mediaarea.net/mediainfo https://mediaarea.net/mediainfo/mediainfo_2_0.xsd" version="2.0">
<creatingLibrary version="18.03" url="https://mediaarea.net/MediaInfo">MediaInfoLib</creatingLibrary>
<media ref="Krtek a buldozer-jdvwqZUEbhc.mkv">
<track type="General">
<UniqueID>101120522676894244607292274887483611459</UniqueID>
<VideoCount>1</VideoCount>
<AudioCount>1</AudioCount>
<FileExtension>mkv</FileExtension>
<Format>Matroska</Format>
<Format_Version>4</Format_Version>
<FileSize>60132643</FileSize>
<Duration>374.101</Duration>
<OverallBitRate>1285912</OverallBitRate>
<FrameRate>25.000</FrameRate>
<FrameCount>9352</FrameCount>
<IsStreamable>Yes</IsStreamable>
<File_Modified_Date>UTC 2018-10-15 07:09:29</File_Modified_Date>
<File_Modified_Date_Local>2018-10-15 09:09:29</File_Modified_Date_Local>
<Encoded_Application>Lavf57.71.100</Encoded_Application>
<Encoded_Library>Lavf57.71.100</Encoded_Library>
<extra>
<ErrorDetectionType>Per level 1</ErrorDetectionType>
</extra>
</track>
<track type="Video">
<StreamOrder>0</StreamOrder>
<ID>1</ID>
<UniqueID>1</UniqueID>
<Format>AVC</Format>
<Format_Profile>High</Format_Profile>
<Format_Level>4</Format_Level>
<Format_Settings_CABAC>Yes</Format_Settings_CABAC>
<Format_Settings_RefFrames>3</Format_Settings_RefFrames>
<CodecID>V_MPEG4/ISO/AVC</CodecID>
<Duration>374.080000000</Duration>
<Width>1920</Width>
<Height>1080</Height>
<Stored_Height>1088</Stored_Height>
<Sampled_Width>1920</Sampled_Width>
<Sampled_Height>1080</Sampled_Height>
<PixelAspectRatio>1.000</PixelAspectRatio>
<DisplayAspectRatio>1.778</DisplayAspectRatio>
<FrameRate_Mode>CFR</FrameRate_Mode>
<FrameRate_Mode_Original>VFR</FrameRate_Mode_Original>
<FrameRate>25.000</FrameRate>
<FrameCount>9352</FrameCount>
<ColorSpace>YUV</ColorSpace>
<ChromaSubsampling>4:2:0</ChromaSubsampling>
<BitDepth>8</BitDepth>
<ScanType>Progressive</ScanType>
<Delay>0.000</Delay>
<Default>Yes</Default>
<Forced>No</Forced>
<colour_range>Limited</colour_range>
<colour_description_present>Yes</colour_description_present>
<colour_primaries>BT.709</colour_primaries>
<transfer_characteristics>BT.709</transfer_characteristics>
<matrix_coefficients>BT.709</matrix_coefficients>
</track>
<track type="Audio">
<StreamOrder>1</StreamOrder>
<ID>2</ID>
<UniqueID>2</UniqueID>
<Format>Opus</Format>
<CodecID>A_OPUS</CodecID>
<Duration>374.101000000</Duration>
<Channels>2</Channels>
<ChannelPositions>Front: L R</ChannelPositions>
<SamplingRate>48000</SamplingRate>
<SamplingCount>17956848</SamplingCount>
<BitDepth>32</BitDepth>
<Compression_Mode>Lossy</Compression_Mode>
<Delay>0.000</Delay>
<Delay_Source>Container</Delay_Source>
<Language>en</Language>
<Default>Yes</Default>
<Forced>No</Forced>
</track>
</media>
</MediaInfo>
现在说我要获取所有ID:
... | xmlstarlet sel -t -v "//ID"
,不打印任何内容。什么?为什么?好吧,事实证明,如果我从第二行的标记中删除所有参数,则相同的选择命令将起作用。现在我不明白,xmlstarlet(可能)工作得很好,我只是缺少了一些魔术标记或语法,因此它可以处理具有定义名称空间的xml。有人可以建议吗?
答案 0 :(得分:0)
您需要使用带有-N
选项的名称空间,并在类似<namespace>:<xpath>
的查询中使用它:
... | xmlstarlet sel -N n="https://mediaarea.net/mediainfo" -t -v "//n:ID"
从帮助页面:
-N
<name>=<value>
-预定义名称空间(名称不带'xmlns:')
例如:xsql = urn:oracle-xsql
允许使用多个-N选项。