Question

我正在学习编程课程，并且被分配了“ Rock，Paper Scissors”游戏来写作。指导者规定，这些函数的名称应与我拥有的相同，并且如果不关闭程序就无法结束游戏循环。出于某种原因，当我运行此代码时，系统会告诉我未定义“随机数”。我究竟做错了什么？谢谢

import random
keepgoing = 1

def main():
    get_computermove()
    get_playermove()
    calculatewinner()

def get_computermove():
    computermove = random.randint(1, 3)
    randomnumber = computermove
    return randomnumber

def get_playermove():
    playermove = input('Please pick rock, paper, or scissors. ')
    return playermove

def calculatewinner():
    if randomumber == 1 and playermove == "rock":
        print('It is a tie!')
    elif randomnumber == 2 and playermove == "paper":
        print('It is a tie!')
    elif randomnumber == 3 and playermove == "scissors":
        print('It is a tie!')
    elif randomnumber == "1" and playermove == "Paper":
        print('Paper covers rock. You win!')
    elif randomnumber == "1" and playermove == "scissors":
        print('Rock breaks scissors. You lose.')
    elif randomnumber == "2" and playermove == "Rock":
        print('Paper covers rock. You lose.')
    elif randomnumber == "2" and playermove == "Scissors":
        print('Scissors cuts paper. You win!')
    elif randomnumber == "3" and playermove == "Rock":
        print('Rock breaks scissors. You win!')
    elif randomnumber == "3" and playermove == "Paper":
        print('Scissors cuts paper. You lose.')

while keepgoing == 1:
    main()

Answer 1

您已经创建了两个randomnumber变量：一个在get_computermove内部，另一个在calculate_winner内部。第二个没有定义值。离开该功能后，第一个消失。相反，请尝试以下操作：保存每个函数的返回值，然后将它们传递到最终例程中。

def main():
    computermove = get_computermove()
    playermove = get_playermove()
    calculatewinner(computermove, playermove)

...
def calculatewinner(randomnumber, playermove):

使用变量名可以做得更好，但这应该使其余代码保持完整。

Answer 2

这是解决此问题的好方法，但是您需要知道，Python中返回的任何内容都不会存储为全局变量，除非您明确地这样做。每当调用get_computermove（）函数时，它都会返回一个“随机数”，但是由于您没有将其存储在任何地方，它会丢失。另外，您还需要将其作为其中一个参数传递给calculatewinner（）函数，以便在函数内部对其进行访问。

请注意，代码的第一行拼写了“ randomnumber”。

Python Rock Paper Scissors游戏

2 个答案: