Question

所以基本上，我试图在RPG Maker中制作一个具有8个方向的玩家移动系统。我以某种方式成功，但仅部分成功。当我试图突然改变方向时。从上到左，字符断断续续，不想先移动所有键就移动。

重力比例已禁用或更像设置为0，主体类型是动态的。

这是一个代码：

using System.Collections;
using System.Collections.Generic;
using UnityEngine;

public class MoveChar : MonoBehaviour {

Rigidbody2D rigid;

public float Speed;

// Use this for initialization
void Start () {

    rigid = GetComponent<Rigidbody2D>();

}

// Update is called once per frame
void Update () {

//        float horiz = Input.GetAxis("Horizontal");

//        float vert = Input.GetAxis("Vertical");

    if(Input.GetKeyDown(KeyCode.W)) //________________________________________MOVING UP

    {
        rigid.velocity = new Vector2(rigid.velocity.x, 1 * Speed);
    }
    else if(Input.GetKeyUp(KeyCode.W))
    {
        rigid.velocity = new Vector2(0, 0);
    }

    if (Input.GetKeyDown(KeyCode.S)) //_______________________________________MOVING DOWN
    {
        rigid.velocity = new Vector2(rigid.velocity.x, -1 * Speed);
    }
    else if (Input.GetKeyUp(KeyCode.S))
    {
        rigid.velocity = new Vector2(0, 0);
    }


    if (Input.GetKeyDown(KeyCode.A)) //_______________________________________MOVING LEFT
    {
        rigid.velocity = new Vector2(-1 * Speed, rigid.velocity.y);
    }
    else if (Input.GetKeyUp(KeyCode.A))
    {
        rigid.velocity = new Vector2(0, 0);
    }

    if (Input.GetKeyDown(KeyCode.D)) //_______________________________________MOVING RIGHT
    {
        rigid.velocity = new Vector2(1 * Speed, rigid.velocity.y);
    }
    else if (Input.GetKeyUp(KeyCode.D))
    {
        rigid.velocity = new Vector2(0, 0);
    }
}

Answer 1

使用Input.GetAxis(axisName)来避免输入代码中的大小写冲突。另外，请使用AddForce与其他刚体完美搭配。

Vector2 oldV = rigid.velocity;
float horiz = Input.GetAxis("Horizontal");
float vert = Input.GetAxis("Vertical");

Vector2 newV = new Vector2(horiz * Speed, vert * Speed);
rigid.AddForce(newV-oldV, ForceMode2D.Impulse);

或者，按住键时，请跟踪自己的轴

public float horiz;
public float vert;

void Start() {
    horiz = 0f;
    vert = 0f;
    if (Input.GetKey(KeyCode.A)) horiz -= 1f;
    if (Input.GetKey(KeyCode.D)) horiz += 1f;
    if (Input.GetKey(KeyCode.S)) vert -= 1f;
    if (Input.GetKey(KeyCode.W)) vert += 1f;
}

void Update () {
    Vector2 oldV = rigid.velocity;

    if(Input.GetKeyDown(KeyCode.W)) vert += 1f;
    else if(Input.GetKeyUp(KeyCode.W)) vert -= 1f;

    if (Input.GetKeyDown(KeyCode.S)) vert -= 1f;
    else if (Input.GetKeyUp(KeyCode.S)) vert += 1f;

    if (Input.GetKeyDown(KeyCode.A)) horiz -= 1f;
    else if (Input.GetKeyUp(KeyCode.A)) horiz += 1f;

    if (Input.GetKeyDown(KeyCode.D)) horiz += 1f;
    else if (Input.GetKeyUp(KeyCode.D)) horiz -= 1f;

    Vector2 newV = new Vector2(horiz * Speed, vert * Speed);
    rigid.AddForce(newV-oldV, ForceMode2D.Impulse);
}

Answer 2

释放按钮只有一个小问题。在不受键影响的方向上施加原始力。整个脚本应如下所示：

void Update()
{
    if (Input.GetKeyDown(KeyCode.W)) //________________________________________MOVING UP
    {
        rigid.velocity = new Vector2(rigid.velocity.x, 1 * Speed);
    }
    else if (Input.GetKeyUp(KeyCode.W))
    {
        rigid.velocity = new Vector2(rigid.velocity.x, 0);
    }

    if (Input.GetKeyDown(KeyCode.S)) //_______________________________________MOVING DOWN
    {
        rigid.velocity = new Vector2(rigid.velocity.x, -1 * Speed);
    }
    else if (Input.GetKeyUp(KeyCode.S))
    {
        rigid.velocity = new Vector2(rigid.velocity.x, 0);
    }


    if (Input.GetKeyDown(KeyCode.A)) //_______________________________________MOVING LEFT
    {
        rigid.velocity = new Vector2(-1 * Speed, rigid.velocity.y);
    }
    else if (Input.GetKeyUp(KeyCode.A))
    {
        rigid.velocity = new Vector2(0, rigid.velocity.y);
    }

    if (Input.GetKeyDown(KeyCode.D)) //_______________________________________MOVING RIGHT
    {
        rigid.velocity = new Vector2(1 * Speed, rigid.velocity.y);
    }
    else if (Input.GetKeyUp(KeyCode.D))
    {
        rigid.velocity = new Vector2(0, rigid.velocity.y);
    }
}

希望对您有帮助。

Unity 2D中的口吃运动

2 个答案: