Question

我已经尝试了所有方法，如果您不选择“ ST”，则它会在while循环中不断循环。我不确定该怎么做，如果有人告诉我，这将非常有帮助。在某些情况下，我在顶部添加了代码。我只需要while循环的帮助。我正在使用while循环，因此，如果他们不选择给定的职位，就必须重新选择。

这是我的代码：

pos = input("What Is Your Choice")

if pos == "ST":
    shot = 8
    print("Shot Is",shot)
    passing = 6
    print("Passing Is",passing)
    pace = 6
    print("Pace Is",pace)
    defending = 2
    print("Defending Is",defending)

if pos == "MID":
    shot = 6
    print("Shot Is",shot)
    passing = 6
    print("Passing Is",passing)
    pace = 6
    print("Pace Is",pace)
    defending = 4
    print("Defending Is",defending)

if pos == "DEF":
    shot = 2
    print("Shot Is",shot)
    passing = 6
    print("Passing Is",passing)
    pace = 4
    print("Pace Is",pace)
    defending = 8
    print("Defending Is",defending)

if pos == "GK":
    dive = 7
    dist = 8
    catch = 7

print(pos)

while pos != "ST" and "MID" and "DEF" and "GK" and "St" and "Mid" and 
"Def" and "Gk":
    print("What Position Do You Want To Play?")
    time.sleep(1)
    print("The Options Are..")
    time.sleep(1)
    print("ST (Striker)")
    time.sleep(1)
    print("MID (Midfielder)")
    time.sleep(1)
    print("DEF (Defender)")
    time.sleep(1)
    print("GK (Goalkeeper)")
    time.sleep(1)

pos = input("What Is Your Choice")

Answer 1

这部分是错误的：

while pos != "ST" and "MID" and "DEF" and "GK" and "St" and "Mid" and "Def" and "Gk":

pos != "ST"被求值，其余字符串不与任何内容进行比较。实际上，该部分的评估方式如下：

while (pos != "ST") and ("MID") and ("DEF") and ("GK") and ("St") and ("Mid") and ("Def") and ("Gk"):

非空字符串始终为True，因此，只要pos != "ST"为True，就永远不会超出循环范围。您可能想做的是：

while pos != "ST" and pos != "MID" and pos != "DEF" and pos != "GK" and pos != "St" and pos != "Mid" and pos != "Def" and pos != "Gk":

但是，正如已经指出的评论之一，您可以只使用in：

while pos not in {"ST", "MID", "DEF", "GK", "St", "Mid", "Def", "Gk"}:

请注意，我在这里使用了set，因为它们提供了效率更高的成员资格测试。在这个小例子中可能没什么大不了，但是它是一个更好的选择。

Answer 2

！=仅适用于紧接其后列出的项目（不使用括号和其他操作）。因此，在您的示例中，您的while循环说“ while位置不等于ST，MID为true，DEF为true，DK为true，Mid为true，Def为true，Gk为true，”。 >

要告诉您的程序在位置不等于ST，MID或DEF等时执行while循环，您必须明确地将其拼写出来-

while pos != "ST" and pos != "MID" and ... and post != "Gk"

Answer 3

while循环永远不会结束，因为您的输入在外部。这是工作代码：

import time
pos = ""


while pos != "ST" and "MID" and "DEF" and "GK" and "St" and "Mid" and "Def" and "Gk":
    print("What Position Do You Want To Play?")
    time.sleep(1)
    print("The Options Are..")
    time.sleep(1)
    print("ST (Striker)")
    time.sleep(1)
    print("MID (Midfielder)")
    time.sleep(1)
    print("DEF (Defender)")
    time.sleep(1)
    print("GK (Goalkeeper)")
    time.sleep(1)

    pos = input("What Is Your Choice")
    break


if pos == "ST":
    shot = 8
    print("Shot Is",shot)
    passing = 6
    print("Passing Is",passing)
    pace = 6
    print("Pace Is",pace)
    defending = 2
    print("Defending Is",defending)

if pos == "MID":
    shot = 6
    print("Shot Is",shot)
    passing = 6
    print("Passing Is",passing)
    pace = 6
    print("Pace Is",pace)
    defending = 4
    print("Defending Is",defending)

if pos == "DEF":
    shot = 2
    print("Shot Is",shot)
    passing = 6
    print("Passing Is",passing)
    pace = 4
    print("Pace Is",pace)
    defending = 8
    print("Defending Is",defending)

if pos == "GK":
    dive = 7
    dist = 8
    catch = 7

    print(pos)

，您必须选择“”，因为它是一个字符串

如何使用逻辑运算符

3 个答案: