Question

我正在尝试使用MARS在位图中绘制一个圆。我已经从Wikipedia转换了c公式，但是我得到的结果是错误的。我以为转换有误，但是我一生都无法弄清楚它是什么。

#Procedure: drawCircle:
#Draw a circle in the center of the input pixel (This will be implemented using the 
#midpoint circle algorithm from https://en.wikipedia.org/wiki/Midpoint_circle_algorithm
#a0 = x0
#a1 = y0
#a2 = color
#a3 = radius
drawCircle:
    #MAKE ROOM ON STACK
    addi        $sp, $sp, -20       #Make room on stack for 1 words
    sw      $ra, 0($sp)     #Store $ra on element 0 of stack
    sw      $a0, 4($sp)     #Store $a0 on element 1 of stack
    sw      $a1, 8($sp)     #Store $a1 on element 2 of stack
    sw      $a2, 12($sp)        #Store $a1 on element 3 of stack
    sw      $a3, 16($sp)        #Store $a1 on element 4 of stack

    #VARIABLES
    move        $t0, $a0            #x0
    move        $t1, $a1            #y0
    move        $t2, $a3            #radius
    addi        $t3, $t2, -1            #x
    li      $t4, 0              #y
    li      $t5, 1              #dx
    li      $t6, 1              #dy
    li      $t7, 0              #Err

    #CALCULATE ERR (dx - (radius << 1))
    sll         $t8, $t2, 1         #Bitshift radius left 1 
    subu        $t7, $t5, $t8           #Subtract dx - shifted radius 

    #While(x >= y)
    circleLoop:
    blt         $t3, $t4, skipCircleLoop    #If x < y, skip circleLoop

    #Draw Dot (x0 + x, y0 + y)
    addu        $a0, $t0, $t3
    addu        $a1, $t1, $t4
    lw          $a2, 12($sp)
    jal         drawDot             #Jump to drawDot

        #Draw Dot (x0 + y, y0 + x)
        addu        $a0, $t0, $t4
        addu        $a1, $t1, $t3
        lw      $a2, 12($sp)
        jal     drawDot             #Jump to drawDot

        #Draw Dot (x0 - y, y0 + x)
        subu        $a0, $t0, $t4
        addu        $a1, $t1, $t3
        lw      $a2, 12($sp)
        jal     drawDot             #Jump to drawDot

        #Draw Dot (x0 - x, y0 + y)
        subu        $a0, $t0, $t3
        addu        $a1, $t1, $t4
        lw      $a2, 12($sp)
        jal     drawDot             #Jump to drawDot

        #Draw Dot (x0 - x, y0 - y)
        subu        $a0, $t0, $t3
        subu        $a1, $t1, $t4
        lw      $a2, 12($sp)
        jal     drawDot             #Jump to drawDot

        #Draw Dot (x0 - y, y0 - x)
        subu        $a0, $t0, $t4
        subu        $a1, $t1, $t3
        lw      $a2, 12($sp)
        jal     drawDot             #Jump to drawDot

        #Draw Dot (x0 + y, y0 - x)
        addu        $a0, $t0, $t4
        subu        $a1, $t1, $t3
        lw      $a2, 12($sp)
        jal     drawDot             #Jump to drawDot

        #Draw Dot (x0 + x, y0 - y)
        addu        $a0, $t0, $t3
        subu        $a1, $t1, $t4
        lw      $a2, 12($sp)
        jal     drawDot             #Jump to drawDot

    #If (err <= 0)
    bgtz        $t7, doElse
    addi        $t4, $t4, 1     #y++
    addu        $t7, $t7, $t6       #err += dy
    addi        $t6, $t6, 2     #dy += 2
    j       circleContinue      #Skip else stmt

    #Else If (err > 0)
    doElse:
    addi        $t3, $t3, -1        #x--
    addi        $t5, $t5, 2     #dx += 2
    sll     $t8, $t2, 1     #Bitshift radius left 1 
    subu        $t9, $t5, $t8       #Subtract dx - shifted radius 
    addu        $t7, $t7, $t9       #err += $t9

    circleContinue:
    #LOOP
    j       circleLoop

    #CONTINUE
    skipCircleLoop:     

    #RESTORE $RA
    lw      $ra, 0($sp)     #Restore $ra from stack
    addi        $sp, $sp, 20        #Readjust stack

我所称的任何程序都不会更改任何t寄存器。我得到的结果具有以下值：x = 10 y = 10颜色= 5半径= 10

Answer 1

我想我已经解决了。问题不是转换，而是位图的大小。似乎当位图较小时，圆最终会环绕。

MIPS：中点圆算法

1 个答案: