尝试在Laravel 5.6中获取非对象的属性时出错

Question

所以我试图遍历对象数组以使用对象中的值更新数据库中的某些值

当我在控制器中运行此循环

foreach($statuses as $status){
            $workflow->statuses()->where('id', $status->id)->update([
                'status' =>  $status->status
            ]);
        };

它给我错误trying to get property of non-object

当我执行`return response（$ request-> statuses）时，这是我在控制台中看到的数据结构

这是完整的控制器

public function workflowStatuses(Request $request, Workflow $workflow)
    {

        // validate form data
        $data = $request->validate([
            'workflow' => 'required|string',
        ]);

            // validate form data
        $oldStatuses = $request->validate([
            'statuses' => 'required|array'
        ]);

        // validate form data
        $newStatuses = $request->validate([
            'newStatuses' => 'required|array',
        ]);


        $workflow->update($data);

        $statuses = $oldStatuses;

        foreach($statuses as $status){
            $workflow->statuses()->where('id', $status['id'])->update([
                'status' =>  $status->status
            ]);
        };

        $workflow->statuses()->saveMany($newStatuses);

        return response($workflow, 200);

    }

Answer 1

您可以将$request->validate()的返回值视为所有请求输入的数组，将其过滤为仅包含正在验证的数据。如果该经过验证的数据包含数组，那么您将拥有一个多维数组。

在这里，$oldStatuses将是一个包含名为statuses的键的数组，该键包含您要查找的实际数组。

$oldStatuses = $request->validate([
   'statuses' => 'required|array'
]);


// $statuses should get 'statuses' out of this validated array
$statuses = $oldStatuses['statuses'];

相反，您可能需要清理它，而不要三次调用validate。通常最好在一次validate（）调用中运行所有验证规则，除非您有充分的理由将它们逻辑上分开。

$validated = $request->validate([
   'workflow' => 'required|string',
   'statuses' => 'required|array',
   'newStatuses' => 'required|array',
]);

$statuses = $validated['statuses'];

Answer 2

尝试：

foreach($statuses as $status){
   $workflow->statuses()->where('id', $status['id'])->update([
   'status' =>  $status['status'] //$status['status'] should also be accessed by key 
   ]);
};