错误:尝试获取非对象的属性

时间:2017-12-09 10:30:28

标签: laravel laravel-5 eloquent

我有表格Authors和表格Uploads,我只是想通过author_id表格中的Uploads获取特定作者的所有上传内容。

为此目的,我的控制器中有一个方法如下:

public function author_works()
    {

        $uploads= Upload::where('author_id', 3)->first();

        return view('author-works')->with('uploads',$uploads);
    }

我的观点是:

  @extends('layouts.app')
@section('content')
    <h1>Uploads</h1>
    @if(count($uploads)>0)
        @foreach($uploads as $upload)
            <div class="well">
                <h3><a href="/uploads/{{$upload->id}}">{{$upload->name}}</a> </h3>
                <small>Written on {{$upload->created_at}}</small>

            </div>
        @endforeach
      {{--  {{$uploads->links()}}--}}
    @else
        <p>No uploads found</p>
    @endif

@endsection

当我在控制器中使用dd($uploads);进行调试时,我看到以下内容,这实际上是正确的记录:

 #attributes: array:9 [▼
    "id" => 7
    "name" => "Fsdf"
    "description" => "fsdfsdffds"
    "created_at" => "2017-12-07 21:29:53"
    "updated_at" => "2017-12-07 21:29:53"
    "user_id" => 1
    "avtor_id" => 3
  ]
  #original: array:9 [▼
    "id" => 7
    "name" => "Fsdf"
    "description" => "fsdfsdffds"
    "created_at" => "2017-12-07 21:29:53"
    "updated_at" => "2017-12-07 21:29:53"
    "user_id" => 1
    "avtor_id" => 3
  ]

有人可以解释我为什么会收到错误吗?

1 个答案:

答案 0 :(得分:2)

当您使用return true方法you're getting an object instead of collection时。使用first()

get()