我有一个Geolocation.js,它获取地理位置并将其记录到控制台。它将导入到index.js文件中,需要使用已记录的lat
和lng
值来替换ll
中的当前硬编码值:
import * as fsAPI from "../data/API_credentials";
import {userGeo} from "../component/Geolocation"
class Helper {
static baseURL() {
return "https://api.foursquare.com/v2";
}
// Client ID, client secret, and version stored in credentials file
static auth(){
const keys = {
client_id: `${fsAPI.client_id}`,
client_secret: `${fsAPI.client_secret}`,
v: `${fsAPI.client_version}`,
// Trying to get data from {userGeo}
// ll: `${userGeo.pos.lat}` + "," + `${userGeo.pos.lng}` //cannot read 'pos' of undefined.
// Line below works
ll: "36.04,-86.74"
}
return Object.keys(keys).map(key => `${key}=${keys[key]}`)
.join("&");
}
我作为userGeo
导入上述代码的代码如下,这是我的错误。我该如何重构才能让我抓住上面lat lng
中的ll
?例如userGeo.pos.lat
。
您可以在上面的// ll: `${userGeo.pos.lat}` + "," + `${userGeo.pos.lng}`
中看到我的失败尝试,并抛出了cannot read 'pos' of undefined.
// Geolocation of user to be used for search query Foursqaure call url
export const userGeo = navigator.geolocation.getCurrentPosition((position) => {
var pos = {
lat: position.coords.latitude,
lng: position.coords.longitude
};
console.log(pos) // works
console.log("Lat: " + pos.lat) // works
});
非常感谢! 本
答案 0 :(得分:1)
navigator.geolocation.getCurrentPosition
是异步的。它接受一个回调作为第一个参数,该参数将在检索位置后被调用。我建议在auth
函数中使用并使用它:
// Geolocation.js
export const getUserGeo = function (options) {
return new Promise(function (resolve, reject) {
navigator.geolocation.getCurrentPosition(resolve, reject, options);
});
}
// Helper.js
import { getUserGeo } from "../component/Geolocation";
class Helper {
static baseURL() {
return "https://api.foursquare.com/v2";
}
static auth(){
return getUserGeo()
.then(position => {
const keys = {
client_id: `${fsAPI.client_id}`,
client_secret: `${fsAPI.client_secret}`,
v: `${fsAPI.client_version}`,
ll: `${position.coords.latitude}` + "," + `${position.coords. longitude}`
};
return Object.keys(keys).map(key => `${key}=${keys[key]}`).join("&");
});
}
请记住,不是auth()
方法是异步的,它会返回Promise
,该值将以Object.keys(keys).map(key =>
$ {key} = $ {keys [key]的值进行解析} ).join("&")