Question

我将尝试在sympy中使用solve函数的结果

public class Building {
private int xSize = 10;             
private int ySize = 10; // and y
private ArrayList<Room> allRooms;
private Person P;

Building (String first){
allRooms = new ArrayList<Room>(); 
setBuilding(first); 
}

 public void setBuilding(String bS) {
 String[] Space;    

    allRooms.clear(); 
    Space = bS.split(";");  
    //defining the x and y coordinate
    String[] buildingSize = Space[0].split(" "); 
    xSize = Integer.parseInt(buildingSize[0]); 
    ySize =Integer.parseInt(buildingSize[1]); 
    allRooms.add(new Room(Space[1]));
    allRooms.add(new Room(Space[2])); 
    allRooms.add(new Room(Space[3])); 
    Person P = new Person (new Point(2,3));
 }


public String toString() {
     String s = "Building size " + xSize +","+ySize + P + '\n'; 
    for (Room r : allRooms) { //for loop 
        s += r.toString();
    }

    return s;  
}



public static void main(String[] args) {
    // TODO Auto-generated method stub
    Building b = new Building("11 11;0 0 5 5 3 5;6 0 10 10 6 6;0 5 5 10 2 5");  // create 
    System.out.println(b.toString());               // and print

}

结果是

from sympy import solve,  expand,

SolutionForPi = (alpha*mu*(-gamma*l*rho + gamma*l - gamma*pi*rho + gamma*pi - l*rho - pi*rho)/(-rho/(rho - 1) + 1) + f*mu)-pi
SolutionForPi = solve(SolutionForPi, pi)

然后我使用sympy.expend函数

[mu*(-alpha*gamma*l*rho**2 + 2*alpha*gamma*l*rho - alpha*gamma*l - alpha*l*rho**2 + alpha*l*rho - f)/(alpha*gamma*mu*rho**2 - 2*alpha*gamma*mu*rho + alpha*gamma*mu + alpha*mu*rho**2 - alpha*mu*rho - 1)]

但是我得到这个错误：

ExpandSolution = expand(SolutionForPi)

我了解这是列表而不是等式，所以我该怎么办？

Answer 1

如果您的解决方案封装在列表中，请访问（单个）列表成员

ExpandSolution = expand(SolutionForPi[0])

SymPy：使用sympy.solve函数的结果

1 个答案: