Question

当前代码：

[HttpPost]
        public JsonResult Listar2()
        {
            var search = Request.Form.GetValues("search[value]")?[0];

            var list = db.Students;

            if (!string.IsNullOrEmpty(search))
            {
                list = list.Where(m => m.name.ToLower().Contains(search.ToLower()) || m.class.ToLower().Contains(search.ToLower()));
            }

            var draw = Request.Form.GetValues("draw")?[0];
            var start = Request.Form.GetValues("start")?[0];
            var length = Request.Form.GetValues("length")?[0];

            var width = length != null ? Convert.ToInt32(length) : 0;
            var skip = start != null ? Convert.ToInt32(start) : 0;

            var totalRecords = list.Count();
            var resultFinal = list.Skip(skip).Take(width).ToList();

            return Json(new
            {
                data = resultFinal,
                draw,
                recordsFiltered = totalRecords,
                recordsTotal = totalRecords
            });
        }

使用上面的代码，我试图集中精力让data$light <- ifelse(data$cigs == 1:5, 1, 0)仅将{{1}中的ifelse到1的值1分配给5（ cigs是每天抽烟的香烟数量，范围从cigs到0）。

Answer 1

尝试%in%

data$light <- ifelse(data$cigs %in% c(1:5), 1, 0)

或等效地

data$light <- ifelse(data$cigs >=1& data$cigs <=5, 1, 0)

R-将测试（以ifelse形式）分配在两个数字之间以生成虚拟变量

1 个答案: