我想单击这两个圆形球并将它们拖动到鼠标当前的鼠标位置,但是它不起作用。
我只想用鼠标单击并拖动球。
未添加某些代码(导入pygame,绘制显示,颜色等)
import pygame
window = pygame.display.set_mode((800,400))
clock = pygame.time.Clock()
##bg = pygame.image.load("bgpool.png")
##window.blit(bg,(0,0))
black = (0,0,0)
yellow = (255,255,0)
class Circle:
def __init__(self,x,y,color,radius):
self.x = x
self.y = y
self.color = color
self.radius = radius
pygame.draw.circle(window, color,(x,y),radius)
def quitgame():
pygame.quit()
quit()
def loop():
cikis = False
while not cikis:
for event in pygame.event.get():
if event.type == pygame.QUIT:
cikis = True
pygame.quit()
quit()
mouse = pygame.mouse.get_pos()
click = pygame.mouse.get_pressed()
bas = pygame.MOUSEBUTTONDOWN
window.fill((255,255,255))
main_circle = Circle(75,175,black,10)
aim_circle = Circle(375,175,yellow,10)
if click[0] == 1:
if mouse[0] >= main_circle.x and mouse[0] <= main_circle.x + main_circle.radius:
if mouse[1] >= main_circle.y and mouse[1] <= main_circle.y + main_circle.radius:
if click[0] == 1:
main_circle.x == mouse[0]
main_circle.y == mouse[1]
clock.tick(120)
pygame.display.update()
loop()
pygame.quit()
quit()
答案 0 :(得分:1)
click = pygame.mouse.get_pressed()
有效的同时,强烈建议使用Pygame的事件,就像您对pygame.QUIT
所做的那样。
因为您没有提供太多代码,所以我添加了最低限度的代码以使代码可运行,并评论了所有修改内容:
import pygame
pygame.init()
window = pygame.display.set_mode((700, 500))
class Circle:
def __init__(self, x, y, color, radius):
# Changed pos to contain both coordinates
self.pos = (x, y)
# Where the radius ends
self.x_boundary = (x - radius, x + radius)
self.y_boundary = (y - radius, y + radius)
self.color = color
self.radius = radius
def recalc_boundary(self):
# Recalculate the boundaries of the circle,
# this is needed whenever the circle is moved
self.x_boundary = (
self.pos[0] - self.radius, self.pos[0] + self.radius
)
self.y_boundary = (
self.pos[1] - self.radius, self.pos[1] + self.radius
)
# Single instantiation of our circle
# didn't add aim_circle because it is irrelevant
# in my answer
main_circle = Circle(75, 175, (255, 0, 0), 10)
# Small lambda function that'll take care of
# checking whether or not a point x is
# within two boundaries.
# This replaces your
# `if mouse[0] >= main_circle.x and mouse[0]
# <= main_circle.x + main_circle.radius:`
# lines
within = lambda x, low, high: low <= x <= high
# Boolean that attests to whether or not the
# user is clicking on our circle
selected = False
while True:
for event in pygame.event.get():
if event.type == pygame.QUIT:
pygame.quit()
# Test for MOUSEBUTTONDOWN events
elif event.type == pygame.MOUSEBUTTONDOWN:
# Left mouse button
if event.button == 1:
pos = pygame.mouse.get_pos()
# Check if the mouse is within
# our circle's limits, to see if the
# user is trying to click on it
if (
within(pos[0], *main_circle.x_boundary)
and within(pos[1], *main_circle.y_boundary)
):
selected = True
elif event.type == pygame.MOUSEBUTTONUP:
# User released mouse buttons
selected = False
if selected:
# Move to mouse position when selected,
# the circle 'follows' the mouse
main_circle.pos = pygame.mouse.get_pos()
main_circle.recalc_boundary()
window.fill((0, 0, 0))
# Moved this draw call to outside
# your class definition
pygame.draw.circle(
window, main_circle.color,
main_circle.pos,
main_circle.radius
)
pygame.display.update()
注意:在每个游戏循环迭代中实例化一个新的Circle
对象是一个坏主意,这将消耗大量CPU,而没有任何工作。我相信您这样做是因为您将圆形绘图调用放置在其中,但您实际上应该将其移入循环中。