读取输入并进行定义

Question

所以我一直在学习python，我正在尝试制作我的第一款游戏，只是自己尝试使用该语言并掌握它。在制作这个猜词游戏时，我遇到了一个输入问题，发现很难克服。

import sys
import os
import random
import time

word_list = ["salt","excess","product","rib","slot","battle"]

#random word from list
random_word = random.choice(word_list)
#defining word_len and making it a string so it can be used in print()
word_len = len(random_word)
word_len = str(word_len)

print("Welcome to the guessing  game")
print("I will give you the length of a random word and you need to guess 
what it is!")
print("The word is " + word_len + " characters long.")
print("The choices are " + "salt " + "excess " + "product" + " rib" + " 
slot" + " and battle" )
print("Good luck!")

#reads the input and defines it
word_guess = sys.stdin.readline()


if word_guess is random_word :
print("Congratulations! You guessed correctly!")
#else which is running despite if being met
else :
print("You lost! :( The word was " + random_word)
#sleep for 5 seconds so the terminal doesnt close
time.sleep(5)

问题是运行代码时会产生以下情况： https://i.imgur.com/Kx2dCiU.png 如果有人可以分享我需要更改的内容，我将不胜感激

Answer 1

更改的代码（仅if else部分）。 readline将换行符保留在字符串中。因此，我们应该在比较之前将其删除。

word_guess = sys.stdin.readline()
word_guess = word_guess[:-1]
if random_word == word_guess :
  print("Congratulations! You guessed correctly!")
#else which is running despite if being met
else :
  print("You lost! :( The word was " + random_word)

Answer 2

is和equals（==）之间的Python区别is运算符可能看起来与equals运算符相同，但是它们并不相同。 is检查两个变量是否指向同一对象，而==符号检查两个变量的值是否相同。

我想在您的代码中再指出一个缺陷。

word_list = ["salt","excess","product","rib","slot","battle"]
#Battle and excess is of same length
#slot and salt is of same length

#random word from list
random_word = random.choice(word_list)
word_len = len(random_word)
word_len = str(word_len)
#As you pick this random, chances of picking length 4 and word 'salt' is good. Whereas you could predict is as 'slot' and get an unexpected error even though you are correct.

因此，请修改列表，例如：

word_list = ["salt","excess","product","rib"]

即使在代码中将'is'更改为'=='后，仍对错误输出进行采样：

Welcome to the guessing  game
I will give you the length of a random word and you need to guess what it is!
The word is 4 characters long.
The choices are salt excess product rib slot and battle

Enter the word : salt
Good luck!
You said salt
You lost! :( The word was slot

SLOT和SALT均为4个字母:) 随时在这里实现其他逻辑。

Answer 3

读取输入并进行定义

word_guess = sys.stdin.readline（） work_guess在末尾附加了\ n值，以便说明为什么不匹配。

替换如果word_guess是random_word：

作者如果word_guess [0：-1] == random_word：

它将起作用。

也请点击here来查看==并且位于python中。

Answer 4

如果要使用sys.stdin.readlines（），则必须指定EOF，否则可以通过输入提示简单地读取输入，两者都很好。EOF is Needed `

Python：尽管相同，输入仍无法识别为变量

4 个答案:

读取输入并进行定义