此处数据集
mydat=structure(list(shop_code = structure(c(1L, 1L, 1L, 1L, 1L, 1L,
1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L,
1L, 1L, 1L), .Label = "00664НСК", class = "factor"), product_id = c(11628L,
11628L, 11628L, 11628L, 11628L, 11628L, 11628L, 11628L, 11628L,
11628L, 11628L, 11628L, 11628L, 11628L, 11628L, 11628L, 11628L,
11628L, 11628L, 11628L, 11628L, 11628L, 11628L, 11628L, 11628L
), doc_date = structure(1:25, .Label = c("2015-01-03 00:00:00.000",
"2015-01-05 00:00:00.000", "2015-01-06 00:00:00.000", "2015-01-07 00:00:00.000",
"2015-01-08 00:00:00.000", "2015-01-09 00:00:00.000", "2015-01-10 00:00:00.000",
"2015-01-11 00:00:00.000", "2015-01-12 00:00:00.000", "2015-01-13 00:00:00.000",
"2015-01-14 00:00:00.000", "2015-01-15 00:00:00.000", "2015-01-16 00:00:00.000",
"2015-01-17 00:00:00.000", "2015-01-18 00:00:00.000", "2015-01-19 00:00:00.000",
"2015-01-20 00:00:00.000", "2015-01-21 00:00:00.000", "2015-01-24 00:00:00.000",
"2015-01-25 00:00:00.000", "2015-01-26 00:00:00.000", "2015-01-27 00:00:00.000",
"2015-01-28 00:00:00.000", "2015-01-29 00:00:00.000", "2015-01-30 00:00:00.000"
), class = "factor"), ship_count = c(12L, 7L, 24L, 18L, 12L,
18L, 6L, 6L, 6L, 18L, 6L, 18L, 12L, 18L, 12L, 10L, 24L, 6L, 6L,
6L, 10L, 6L, 10L, 70L, 100L), mark_1 = c(1L, 1L, 0L, 1L, 1L,
0L, 0L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 0L, 0L,
1L, 1L, 0L, 1L), outputer = c(8L, 8L, 8L, 8L, 8L, 8L, 6L, 6L,
6L, 12L, 6L, 12L, 12L, 12L, 12L, 10L, 12L, 6L, 6L, 6L, 10L, 6L,
10L, 12L, 12L), y = c(1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 0L,
0L, 0L, 1L, 1L, 1L, 0L, 0L, 0L, 0L, 0L, 1L, 0L, 0L, 1L, 1L)), .Names = c("shop_code",
"product_id", "doc_date", "ship_count", "mark_1", "outputer",
"y"), class = "data.frame", row.names = c(NA, -25L))
我需要遵守以下条件: 如果y = 1并且mark1 = 1,则必须将mark1的输出者替换为输出变量中y = 0和mark1 = 1的第一个值。
如果在输出器中用于Y = 0和mark1 = 1的第一个值大于ship_count,则在输出器中留下ship_count的实际值
标记1的输出类别为零,我们不会碰。
此操作必须由ship_code + product_id组完成
所以想要的输出
shop_code product_id doc_date ship_count mark_1 outputer y
1 00664НСК 11628 2015-01-03 00:00:00.000 12 1 *12 1
2 00664НСК 11628 2015-01-05 00:00:00.000 7 1 *7 1
3 00664НСК 11628 2015-01-06 00:00:00.000 24 0 24 1
4 00664НСК 11628 2015-01-07 00:00:00.000 18 1 *12 1
5 00664НСК 11628 2015-01-08 00:00:00.000 12 1 *12 1
6 00664НСК 11628 2015-01-09 00:00:00.000 18 0 18 1
7 00664НСК 11628 2015-01-10 00:00:00.000 6 0 6 1
8 00664НСК 11628 2015-01-11 00:00:00.000 6 1 6 1
9 00664НСК 11628 2015-01-12 00:00:00.000 6 1 6 1
10 00664НСК 11628 2015-01-13 00:00:00.000 18 1 *12 0
11 00664НСК 11628 2015-01-14 00:00:00.000 6 1 6 0
12 00664НСК 11628 2015-01-15 00:00:00.000 18 1 12 0
13 00664НСК 11628 2015-01-16 00:00:00.000 12 1 *10 1
14 00664НСК 11628 2015-01-17 00:00:00.000 18 1 *10 1
15 00664НСК 11628 2015-01-18 00:00:00.000 12 1 *10 1
16 00664НСК 11628 2015-01-19 00:00:00.000 10 1 10 0
17 00664НСК 11628 2015-01-20 00:00:00.000 24 1 12 0
18 00664НСК 11628 2015-01-21 00:00:00.000 6 1 6 0
19 00664НСК 11628 2015-01-24 00:00:00.000 6 1 6 0
20 00664НСК 11628 2015-01-25 00:00:00.000 6 0 6 0
21 00664НСК 11628 2015-01-26 00:00:00.000 10 0 10 1
22 00664НСК 11628 2015-01-27 00:00:00.000 6 1 6 1
23 00664НСК 11628 2015-01-28 00:00:00.000 20 1 *12 0
24 00664НСК 11628 2015-01-29 00:00:00.000 70 1 12 0
25 00664НСК 11628 2015-01-30 00:00:00.000 100 1 12 1
*标记为替换值
答案 0 :(得分:1)
我的看法:
<item name="android:maxLines">1</item>