Question

因此，我正在编写一个比较包装箱体积的程序...但是我需要使其运行，以便不会打印小于1的值并提示错误消息。（即“第一个框是第二个框的大小的0.5倍”或“第一个框是第二个框的大小的0倍”）-而是我希望它打印“错误：请输入一个更大的有效数字大于1“

这是我要修复的代码部分：

if (volume1 == volume2) {
        System.out.println("The first box is the same size as the second box");
    }else if(volume1 >= 0 || volume2 >= 0){
        System.out.println("Error. Please enter a valid number greater than 0");
    }else {
        String bigger = "first box";
        String smaller = "second box";
        double ratio = volume1 / volume2;
        if (volume2 > volume1) {
            bigger = "second box";
            smaller = "first box";
            ratio = volume2 / volume1;
        }
        String compare;
        switch((int) ratio) {
        case 1: compare = " is slightly bigger than "; 
        break;
        case 2: compare = " is twice the size of "; 
        break;
        case 3: compare = " is triple the size of ";
        break;
        case 4: compare = " is quadruple the size of "; 
        break;
        default: compare = " is " + (int) ratio + " times the size of ";
        break;
        }

        System.out.println("The " + bigger + compare + smaller);
    }

我希望这足以解释我的问题所在。从我学到的知识来看，我认为switch语句不会有条件，并且由于int比率的结构方式，我在测试时始终显示0。有什么建议吗？

Answer 1

好的，我希望您的问题正确无误:) 好吧，您可以将if语句添加到默认分支：

// Here the Code till default
default:
    if (ratio < 1) {
        System.err.println("Error: Please enter a valid number greater than 1");
        return; // You should consider to return out of the method here otherwise "The" still gets printed for no reason :)
    } else compare = " is " + (int) ratio + " times the size of ";
}
// Rest of Code

这应该可以完成：）

禁止程序输入小于1的数字（否则/切换）

1 个答案: