Question

对于以下给定的架构，能否请我指导如何使用oracle和sqlplus编写简单的数据挖掘查询？

CREATE TABLE Location(Location_id NUMBER(5) NOT NULL, Location_name varchar(15) NOT NULL,PRIMARY KEY (Location_id));


CREATE TABLE Customer(customer_id NUMBER(5) NOT NULL, customer_name varchar(15) NOT NULL, customer_credit NUMBER(6) NOT NULL, PRIMARY KEY (customer_id));


CREATE TABLE Product(product_id NUMBER(5) NOT NULL, product_name varchar(10) NOT NULL, product_price NUMBER(6) NOT NULL, product_quantity NUMBER(6) NOT NULL, PRIMARY KEY (product_id));


CREATE TABLE Supplier(supplier_id NUMBER(5) NOT NULL, supplier_name varchar(15) NOT NULL, supplier_quantity NUMBER(5) NOT NULL,PRIMARY KEY (supplier_id));


CREATE TABLE Store (customer_id NUMBER(5) NOT NULL, supplier_id NUMBER(5) NOT NULL, product_id NUMBER(5) NOT NULL, location_id NUMBER(5) NOT NULL,sale NUMBER(9) NOT NULL,category varchar(9) NOT NULL);


ALTER TABLE Store ADD CONSTRAINT Store_fk0 FOREIGN KEY (customer_id) REFERENCES Customer(customer_id);

ALTER TABLE Store ADD CONSTRAINT Store_fk1 FOREIGN KEY (supplier_id) REFERENCES Supplier(supplier_id);

ALTER TABLE Store ADD CONSTRAINT Store_fk2 FOREIGN KEY (product_id) REFERENCES Product(product_id);

ALTER TABLE Store ADD CONSTRAINT Store_fk3 FOREIGN KEY (location_id) REFERENCES Location(Location_id);

我有以下我编写的OLAP查询，与数据挖掘查询没什么不同。还可以指导我如何针对以下内容编写更复杂的查询：

SELECT CUSTOMER.CUSTOMER_NAME,PRODUCT.PRODUCT_NAME,SALE FROM STORE INNER JOIN CUSTOMER ON STORE.CUSTOMER_ID = CUSTOMER.CUSTOMER_ID INNER JOIN PRODUCT ON STORE.PRODUCT_ID = PRODUCT.PRODUCT_ID WHERE STORE.SALE = (SELECT MAX(SALE) FROM STORE);

我将不胜感激。

Answer 1

这个问题太含糊，无法给出很好的答案。有关数据挖掘的更多信息，请参阅Oracle Data Mining。数据挖掘从一个简单的查询开始，例如：

BEGIN
  DBMS_PREDICTIVE_ANALYTICS.EXPLAIN(
    data_table_name     => 'mining_data_build_v',
    explain_column_name => 'affinity_card',
    result_table_name   => 'ai_explain_output');
END;
/

天空是极限...

如何为以下架构编写简单的数据挖掘查询？

1 个答案: