Question

我的桌子：
音乐家（id，mname，aname，百分比（年龄费用））
歌手（身份证，性别）
乐器演奏家（id，乐器）
代理人（aname，street，city，zip）
节日（标题，地点，日期，编辑）
事件（标题，edate，etime）
已预订（ID，标题（Event.title），edate，etime，salary）

每个节日，找到代理商，这个节日的整体利润是最高的。提供了电影节的名称，代理商名称及其整体利润。
Festival.title =＆＃34;秋节＆＃34;和工资<8000，查找仅参加活动的日期和时间乐器演奏者，此次活动的乐器演奏者人数最少。

1

select f1.title , aname , sum (salary*percentage/100) as feeAgent 
from festival as f1 , booked , musician 
where booked.id=musician.id and booked.edate between f1.sdate and f1.edate
group by  f1.title , aname
having sum (salary*percentage/100)>any(select sum (salary*percentage/100)
                                       from festival as f1 , booked , musician 
                                       where booked.id=musician.id and     booked.edate between f1.sdate and f1.edate
                                       group by musician.aname)

2

select event.edate, event.etime
from event, festival as f1, booked natural join musician natural join instrumentalist 
where event.title=f1.title and f1.title Like 'spring%' and booked.salary<8000 and booked.edate between f1.sdate and f1.edate
group by event.edate, event.etime
having count(booked.title)<all(select count(*)
           from event,festival as f1,booked natural join musician natural join instrumentalist
           where event.title=f1.title and f1.title Like 'spring%' and booked.salary<8000 and booked.edate between f1.sdate and f1.edate
           group by booked.title)

如何在SQL中编写以下查询

0 个答案: