Question

我必须创建一个实时报告。为此，我必须为给定一天的每个小时编写条件。在下面的代码中，条件检查一周中的当前日期，然后检查当前时间，并根据该条件生成报告。

protected void sample()
{
    TimeSpan zerothHour = new TimeSpan(00, 0, 0);
    TimeSpan firstHour = new TimeSpan(01, 0, 0);
    TimeSpan secondHour = new TimeSpan(02, 0, 0);
    TimeSpan thirdHour = new TimeSpan(03, 0, 0);
    TimeSpan fourthHour = new TimeSpan(04, 0, 0);
    TimeSpan fifthHour = new TimeSpan(05, 0, 0);
    TimeSpan sixthHour = new TimeSpan(06, 0, 0); 
    // and so on until the twentyfourth hour
    if (DateTime.Today.DayOfWeek == DayOfWeek.Monday)
    {
        if (DateTime.Now.TimeOfDay >= sixthHour && DateTime.Now.TimeOfDay <= seventhHour)
        {
            //MySql query here
            string MyConString = ConfigurationManager.ConnectionStrings["connStr"].ConnectionString;
            MySqlConnection connection = new MySqlConnection(MyConString);
            string agentlogin = "SELECT agentlogin FROM agentdetails WHERE location = 'PNQ10-Pune' AND shift IN('6:00-15-00', '22:00-7:00') AND Mon = 'W'";
            MySqlCommand cmd = new MySqlCommand(agentlogin, connection);
            connection.Open();
            MySqlDataReader rdr = cmd.ExecuteReader();
            while (rdr.Read())
            {
               //lblagentlogin.Text += rdr["agentlogin"] + Environment.NewLine;
                sqlList.Add(Convert.ToString(rdr["agentlogin"]));
            }
        }
        else if(DateTime.Now.TimeOfDay >= seventhHour && DateTime.Now.TimeOfDay <= eigthHour)
        {

        }
        else if (DateTime.Now.TimeOfDay >= eigthHour && DateTime.Now.TimeOfDay <= ninthHour)
        {

        }
        else if (DateTime.Now.TimeOfDay >= ninthHour && DateTime.Now.TimeOfDay <= tenthHour)
        {

        }
        else if (DateTime.Now.TimeOfDay >= tenthHour && DateTime.Now.TimeOfDay <= eleventhHour)
        {

        }
        // and so on for the entire cycle of time
    }
}

上面的代码仅适用于星期一，我也必须在一周的其他六天内做同样的事情。当我在每个条件中添加查询时，将像几百行。

是否有更好的方法可以完成此任务而无需编写数百行代码？

Answer 1

这对您有用吗？

client.connect()

甚至：

var sqls = new []
{
    "select x from y",
    "select w from q",
    // etc - 24 options
};

var sql = sqls[DateTime.Now.Hour];

如果您想使用var sqls = new Action[] { () => { /* sql for midnight */ }, () => { /* sql for 1 am */ }, // etc () => { /* sql for 11 pm */ }, }; var sql = sqls[DateTime.Now.Hour]; sql.Invoke();和DayOfWeek，则可以使用：

Hour

根据评论和其他答案，这是一种更简洁的方法：

var sqls = new string[][]
{
    new [] { "select x from y", "select w from q", },
    new [] { "select x from y", "select w from q", },
    new [] { "select x from y", "select w from q", },
    new [] { "select x from y", "select w from q", },
    new [] { "select x from y", "select w from q", },
    new [] { "select x from y", "select w from q", },
    new [] { "select x from y", "select w from q", },
};

var sql = sqls[(int)DateTime.Now.DayOfWeek][DateTime.Now.Hour];

Answer 2

听起来您可以通过动态生成SQL来极大地简化代码。我有点猜测，因为我不完全了解您的数据模型，但有以下几点：

var dayColumns = new [] { "Sun", "Mon", "Tue", "Wed", "Thu", "Fri", "Sat" };
var currentDayColumn = dayColumns[(int) DateTime.Now.DayOfWeek];

string shifts;

switch (DateTime.Now.Hour) {
  case 0:
    shifts = "('22:00-7:00')"
    break;
  case 6:
    shifts = "('22:00-7:00', '6:00-15:00')"
    break;
  //TODO - more cases
}

string sql = "SELECT agentlogin FROM agentdetails WHERE location = 'PNQ10-Pune' AND shift IN " + shifts + " AND " + currentDayColumn + " = 'W'";

如果您可以将班次更改为带有开始和结束时间的两列，则可以像这样进一步优化它：

var hour = DateTime.Now.Hour

string sql = "SELECT agentlogin FROM agentdetails WHERE location = 'PNQ10-Pune' AND " + hour + " >= shift_start_hour AND " + hour + " < shift_end_hour AND " + currentDayColumn + " = 'W'";

Answer 3

假设您的SQL也取决于WeekDay + Hour（否则就没有多大意义了？），您可以执行以下操作：

protected void sample()
{
    var now = DateTime.Now;
    var sql = GetSql(now.DayOfWeek, now.Hour);
    // execute sql
}

protected string GetSql(DayOfWeek dayofweek, int hour)
{
    // generate sql, using "(int)dayofweek" if needed
}

使用C＃

3 个答案: