在javascript中简化if .. else

Question

我的思绪是空白的，我想不出解决方案......

我有以下代码：

if (onlySelected === true) {
    if (r.selected == true) {
        result.push(pushValue);
    }
}
else {
    result.push(pushValue);
}

如何将此代码简化为：

if (condition) { result.push(pushValue) } 

Answer 1

试试这个：

if (!onlySelected || r.selected){
    result.push(pushValue);
}

或者如果你绝对需要类型相等而不仅仅是真实性：

if (onlySelected !== true || r.selected){
    result.push(pushValue);
}

Answer 2

if(onlySelected === false || r.selected == true) {
    result.push(pushValue);
}

Answer 3

(!onlySelected || r.selected) && result.push(pushValue);

Answer 4

if( (onlySelected === true && r.selected === true) || 1) {
    result.push(value)
}

Answer 5

我认为这样可行：

if(!onlySelected || (onlySelected && r.selected))
    result.push(pushValue);