我要制作自己的python嗅探器,但在解压缩arp协议标头时遇到问题。
这是我的代码:
def Sniffer():
try:
# AF_PACKET, That's basically packet level.
# 0X0003, That's every packet. (We can find it here: /usr/include/linux/if_ether.h)
SK = socket.socket(socket.AF_PACKET, socket.SOCK_RAW, socket.ntohs(0x0003))
except socket.error as MSG:
print "Socket creation error:\n", MSG
try:
while True:
Receive = SK.recvfrom(65565)
Packet = Receive[0]
Ethernet(Packet)
except socket.error as MSG:
print "Receive error:\n", MSG
# Ethernet Decapsulation (We need EtherType field value)
def Ethernet(Packet):
ETHERNET_LENGTH = 14
ETHERNET_HEADER = Packet[:ETHERNET_LENGTH]
ETHERNET_HEADER_UNPACK = struct.unpack("!6s6sH", ETHERNET_HEADER)
EtherType = ETHERNET_HEADER_UNPACK[2]
print EtherType
if EtherType == 2054:
ARP(ETHERNET_LENGTH, Packet)
if EtherType == 2048:
IPV4(Packet)
# ARP Decapsulation (We need OPCODE field value)
def ARP(ETHERNET_LENGTH, Packet):
ARP_LENGTH = 42
ARP_HEADER = Packet[ETHERNET_LENGTH:ARP_LENGTH]
ARP_HEADER_UNPACK = struct.unpack("!2s2s1s1s2s6s4s6s4s", ARP_HEADER)
OPCODE = ARP_HEADER_UNPACK[4]
if OPCODE == 1:
print "ARP Request (Some one scann your network)"
那是我的错误:
Traceback (most recent call last):
File "HoneySniffer.py", line 130, in <module>
Sniffer()
File "HoneySniffer.py", line 22, in Sniffer
Ethernet(Packet)
File "HoneySniffer.py", line 38, in Ethernet
ARP(ETHERNET_LENGTH, Packet)
File "HoneySniffer.py", line 48, in ARP
ARP_HEADER_UNPACK = struct.unpack("!2s2s1s1s2s6s4s6s4s", ARP_HEADER)
struct.error: unpack requires a string argument of length 28
为什么会这样?
我该如何解决?
答案 0 :(得分:0)
我遇到了完全相同的问题,我使用您的参考链接Python arp sniffing raw socket no reply packets解决了这个问题,并很少进行研究。
conn=socket.socket(socket.AF_PACKET,socket.SOCK_RAW,socket.ntohs(0x0003))
def arp_header(packet):
(a ,b ,c ,d ,e ,f ,g ,h ,i ) = struct.unpack('2s2s1s1s2s6s4s6s4s',packet[14:42])
hw_type=(binascii.hexlify(a)).decode('utf-8')
proto_type=(binascii.hexlify(b)).decode('utf-8')
hw_size=(binascii.hexlify(c)).decode('utf-8')
proto_size=(binascii.hexlify(d)).decode('utf-8')
opcode=(binascii.hexlify(e)).decode('utf-8')
return (hw_type,proto_type,hw_size,proto_size,opcode,socket.inet_ntoa(g),socket.inet_ntoa(i))
使用struct.unpack('2s2s1s1s2s6s4s6s4s',packet[14:42])
不是struct.unpack('!2s2s1s1s2s6s4s6s4s',packet[14:42])
这解决了我的struct.error: unpack requires a string argument of length 28
错误
由于我的项目要求,我还使用了单个变量,
现在,为了进行调试,我使用了print(packet[14:42])
-这给了我字节十六进制字面量(例如b'\x00\x01\x08\x00\x06\x04\x00\x01\xe4\x11[I&\xbe\n\x00.....
等)
所以我必须在使用hexlify之后在utf-8中解码,因为hexlify再次将字节对象返回给我。
我使用的Python版本:3.6.5
日期:2019年4月3日
结果:- Arp Packet:
- H/W Type: 0001, Protocol Type: 0800, H/W Size: 06 ,Protocol Size: 04
- Opcode: 0001, Source IP: 10.0.15.141, Destination IP: 10.0.10.2
判决:这种方法对我有用,我希望它也对您有用:)