Question

我有一张包含类似数据的表，我正在寻找一种将[city]和[street]字段合并为一个字段的方法。 [street]字段是[city]字段的子字符串，可在[city]字段中找到总和预期结果如下：

rocket_contrib

如何在mssql中做到这一点？

city/street   value1    value2  value3  total
Wien            16        50      6       72
Quadenstrabe    14        46      1       61
Laberlsteg      2         4       5       11
Hamburg         7         9       5       21
Esplanade       3         7       4       14
Drehbahn        4         2       1       7

Answer 1

只要您修复了数据类型并且不使用nvarchar来存储int，就可以了：

SELECT ISNULL(street, city) AS CityStreet,
       SUM([Value1]) AS Value1,
       SUM([Value2]) AS Value2,
       SUM([Value3]) AS Value3,
       SUM(Total) AS Total
FROM #CITY_TABLE
GROUP BY city, street WITH ROLLUP
HAVING city IS NOT NULL
ORDER BY CityStreet DESC;

Answer 2

如果Value1，Value2，Value3和Total的数据类型为int，那么您的生活会容易得多。但是，有了您拥有的东西：

SELECT 
    CITY [City/Street],
    SUM(convert(int,VALUE1)) [Value1],
    SUM(convert(int,VALUE2)) [Value2],
    SUM(convert(int,VALUE3)) [Value3],
    SUM(convert(int,TOTAL)) [Value1] from 
[dbo].#CITY_TABLE GROUP BY CITY
UNION
SELECT 
    STREET, 
    convert(int,value1), 
    convert(int,value2), 
    convert(int,value3),
    convert(int,total) 
from [dbo].#CITY_TABLE

Answer 3

我想我会这样做：

select v.city_street, sum(t.value1) as value1, sum(t.value2) as value2, sum(t.value3) as value3
from #CityTable ct cross apply
     (values (city), (street)
     ) v(city_street)
group by city_street;

这假定数字实际上是存储为数字而不是字符串。

字段作为子字符串

3 个答案: