json.Unmarshal(body, data)
我希望data
求和为一个数字。
假设print ('Welcome to BirthPath Calculator')
Day = input('Input you day of Birth (1-31): ')
Month = input('Input your month of birth (1-12): ')
Year = input ('Input your year of birth: ')
Day = int(Day)
Month = int(Month)
Year = int(Year)
Birthpath = Day + Month + Year
sum(Birthpath)
print ('This is your Birth Path: '+str(Birthpath))
的值为2014,我想将其总和为2 + 0 + 1 + 4 = 7。
答案 0 :(得分:0)
获取数字的总和是一个古老的经典问题:
def sum_of_digits(number):
sum = 0
while number > 0:
remainder = number % 10
sum += remainder
number //= 10
return sum
答案 1 :(得分:0)
可以将字符串视为列表。因此,如果您将天,月,年的总和制成字符串,然后对其进行循环遍历
print('Welcome to BirthPath Calculator')
day = int(input('Input you day of Birth (1-31): '))
month = int(input('Input your month of birth (1-12): '))
year = int(input('Input your year of birth: '))
total = day + month + year
birthpath = 0
for digit in str(total):
birthpath += int(digit)
print('This is your Birth Path: ' + str(birthpath))
您还可以使用列表推导来使它简短一些。
print('Welcome to BirthPath Calculator')
day = int(input('Input you day of Birth (1-31): '))
month = int(input('Input your month of birth (1-12): '))
year = int(input('Input your year of birth: '))
total = day + month + year
birthpath = sum(int(digit) for digit in str(total))
print('This is your Birth Path: '+str(birthpath))
答案 2 :(得分:0)
这个简单的班轮就行了!
Birthpath = 2014
sum(int(i) for i in str(Birthpath))