Question

如何降低以下代码的时间复杂度？

我必须检查查询中的单词是否存在于句子中并打印句子编号，否则打印“ -1”。

单词的顺序在查询中无关紧要。它们应该出现在句子中。

课程结果{

static boolean o=false;    

public static void textQueries(List<String> sentences, List<String> queries) {
// Write your code here
    String[] s, se;
    ArrayList<HashSet<Integer>> arr=new ArrayList<>();

    for(int i=0; i<queries.size(); i++) {
        s=queries.get(i).split(" ");
        HashSet<String> set=new HashSet<>(Arrays.asList(s));
        for(String str : set) {
            HashSet<Integer> q=new HashSet<>();
            for(int j=0; j<sentences.size(); j++) {
                se=sentences.get(j).split(" ");
                HashSet<String> sen=new HashSet<>(Arrays.asList(se));
                if(sen.contains(str)) {
                    q.add(j);
                }
            }
            arr.add(q);
        }
        for(int d=0; d<sentences.size(); d++) {
            print(d, arr);
        }
        if(o==false)
            System.out.print("-1");
        System.out.println();
        arr.clear();
        o=false;
    }

}

public static void print(int d, ArrayList<HashSet<Integer>> arr) {
    for(int a=0; a<arr.size(); a++) {
        HashSet<Integer> st=arr.get(a);
        if(!st.contains(d))
            return;
    }
    o=true;
    System.out.print(d+" ");
}

}

Answer 1

这是我认为是改进的版本：

    import java.util.Arrays;
    import java.util.List;

    public class Main {
        public static void main(String[] args) {
            List<String> sentences = Arrays.asList("a bc def", "bc, ajj");
            List<String> queries = Arrays.asList("a bc def");
            textQueries(sentences, queries);
        }

        public static void textQueries(List<String> sentences, List<String> queries) {
            int counter = 0;
            outer:
            for (String sentence : sentences) {
                System.out.println("Process sentence: " + sentence + " nr. " + (++counter));
                List<String> sentenceWords = Arrays.asList((sentence.split(" ")));
                for (String query : queries) {

                    if (sentenceWords.containsAll(Arrays.asList((query.split(" "))))) {
                        System.out.println(counter);
                        continue outer;
                    }
                }
                System.out.println(-1);
            }
        }
    }

Answer 2

<div>
    <input type="file" multiple=""><br>
    <button>Add Table</button><br>
    <div>
        <table style="display: inline-table;">
            <tbody>
                <tr>
                    <td>
                        <input type="file" multiple=""><br>
                        <button>Add Table</button><br>
                        <textarea placeholder="Write some text"></textarea>
                    </td>
                    <td>
                        <input type="file" multiple=""><br>
                        <button>Add Table</button><br>
                        <textarea placeholder="Write some text"></textarea>
                    </td>
                    <td>
                        <button style="margin-left: 100px;">x</button>
                    </td>
                </tr>
                <tr>
                    <td>
                        <input type="file" multiple=""><br>
                        <button>Add Table</button><br>
                        <textarea placeholder="Write some text"></textarea>  
                    </td>
                    <td>
                        <input type="file" multiple=""><br>
                        <button>Add Table</button><br>
                        <textarea placeholder="Write some text"></textarea>
                    </td>
                    <td>
                        <button style="margin-left: 100px;">x</button>
                    </td>
                </tr>
            </tbody>
        </table>
        <button style="margin-left: 100px;">x</button>
    </div>
</div>

如何减少以下代码的时间复杂度？

2 个答案: