从response.body获取数据在android中给出了空的uisng改造

Question

嘿，我正在尝试通过对node.js后端进行改造来从我的api中获取数据，然后将其设置为Textview。我能够成功连接到api，但是当我尝试将文本设置为textview时，它给我带来了问题。当我尝试使用此功能来设置文本时，我在pojo中有一个功能 getCompanyname 。当我在Toast中尝试该功能时，它在Textview中什么都没有显示强>，所以我认为我的方法具有空值，但我找不到问题。以下是必需的代码

1） RequestInterface代码

public interface RetrofitInterface {

@POST("logins")
Call<ServerResponse> operation(@Body ServerRequest request);
@GET("getbusinessprofile/{username}")
Call<CompanyInfo> getCompanydetails(@Path("username")String username);
}

2）仪表板碎片

public void getCompanyData(String username){

           Retrofit retrofit = new Retrofit.Builder()
                              .baseUrl(Constants.BASE_URL)
                              .addConverterFactory(GsonConverterFactory.create())
                              .build();

    RetrofitInterface requestInterface = retrofit.create(RetrofitInterface.class);
    Call<CompanyInfo> callResponse = requestInterface.getCompanydetails(username);

    callResponse.enqueue(new Callback<CompanyInfo>() {
        @Override
        public void onResponse(Call<CompanyInfo> call, Response<CompanyInfo> response) {

           CompanyInfo info=response.body();
           comp_text.setText(info.getCompanyname());
           mail_text.setText(info.getEmail());
           gst_text.setText(info.getGstNo());
            Toast.makeText(getActivity(), "Company name-> "+info.getCompanyname(), Toast.LENGTH_SHORT).show();


        }

我的getCompanyname，getGST，getEmail全部为空

这是我在控制台上的json响应

{"companyname":"hitouch","email":"a@b.com","gst_no":"12354"}

3）** CompanyInfo.java

public class CompanyInfo {

@SerializedName("companyname")
@Expose
private String companyname;
@SerializedName("email")
@Expose
private String email;
@SerializedName("gst_no")
@Expose
private String gstNo;

public String getCompanyname() {
    return companyname;
}

public void setCompanyname(String companyname) {
    this.companyname = companyname;
}

public String getEmail() {
    return email;
}

public void setEmail(String email) {
    this.email = email;
}

public String getGstNo() {
    return gstNo;
}

public void setGstNo(String gstNo) {
    this.gstNo = gstNo;
}

}

请给我一些建议，如果您愿意，我可以发布自己的node.js后端代码

谢谢!!

修改

Answer 1

因为响应是这样的

{
    "statusCode": 200,
    "headers": {
        "Content-Type": "application/json"
    },
    "body": { "companyname": "hitouch", "email": "a@b.com", "gst_no": "12354" }
}

您必须像这样使用pojo

public class CompanyInfoResponse {
    @SerializedName("statusCode")
    int statusCode;

    @SerializedName("headers")
    Map<String, String> headers;        

    @SerializedName("body")
    CompanyInfo companyInfo;
}

更改为

@GET("getbusinessprofile/{username}")
Call<ApiResponse<CompanyInfo>> 
        getCompanydetails(@Path("username")String username);

获取实际数据

CompanyInfo companyInfo = response.body().getBody();

如果您想将其应用于EmployeeInfo等不同类型的Response，则可以使用这样的包装器

public class ApiResponse<T> {
    private transient boolean isSuccess;

    @SerializedName("statusCode")
    private int statusCode;
    @SerializedName("headers")
    Map<String, String> headers;
    @SerializedName("body")
    private T body;

    @Nullable
    public int getStatusCode() {
        return statusCode;
    }

    @Nullable
    public Map<String, String> getHeaders() {
        return headers;
    }

    @Nullable
    public T getBody() {
        return body;
    }
}

然后这样声明

@GET("getbusinessprofile/{username}")
Call<ApiResponse<CompanyInfo>> getCompanydetails(@Path("username")String username);

@GET("getbusinessprofile/{username}")
Call<ApiResponse<EmployeeInfo>> getEmployeeDetails(@Path("username")String username);

获取实际数据

CompanyInfo companyInfo = response.body().getBody();
EmployeeInfo empInfo = response.body().getBody();