如何在pymodbus中使用自定义功能代码实现消息?

时间:2018-10-21 20:10:28

标签: pymodbus pymodbus3

我当前正在尝试实现具有自定义功能代码的modbus请求。该实现基于以下示例:custom_message.py

import struct
from pymodbus.pdu import ModbusRequest, ModbusResponse
from pymodbus.client.sync import ModbusTcpClient

client = ModbusTcpClient('192.168.0.55')
connection = client.connect()

class CustomModbusResponse(ModbusResponse):
    # some fancy decoding should be done here..
    pass

class CustomModbusRequest(ModbusRequest):
    function_code = 55

    def __init__(self, address):
        ModbusRequest.__init__(self)
        self.address = address
        self.count = 1

    def encode(self):
        return struct.pack('>HH', self.address, self.count)

    def decode(self, data):
        self.address, self.count = struct.unpack('>HH', data)

    def execute(self, context):
        if not (1 <= self.count <= 0x7d0):
            return self.doException(ModbusExceptions.IllegalValue)
        if not context.validate(self.function_code, self.address, self.count):
            return self.doException(ModbusExceptions.IllegalAddress)
        values = context.getValues(self.function_code, self.address,
                                   self.count)
        return CustomModbusResponse(values)

request = CustomModbusRequest(0)
result = client.execute(request)
print(result)

请求按预期方式工作。我可以在网络层上看到正确的响应。但是我无法解析结果。 Pymodbus引发以下错误:

DEBUG:pymodbus.factory:Factory Response[55]
ERROR:pymodbus.factory:Unable to decode response Modbus Error: Unknown response 55
ERROR:pymodbus.transaction:Modbus Error: [Input/Output] Unable to decode request

该示例指出,在这种情况下,我将必须:

  

如果您实现了当前未实现的新方法,则您   必须在ClientDecoder工厂中注册请求和响应。

是否有一种优雅的方式来执行此操作而不修补库?

0 个答案:

没有答案