示例图片:
因此,我想逐行转到水平,并获得白色或黑色像素的每个连续集的像素宽度和顺序。
想法是将每行中的数据发送到解码器,一旦解码成功,扫描将停止。有点像是要在损坏的条形码上运行激光条形码扫描仪,直到读取为止。
答案 0 :(得分:1)
好的,我自己解决了这个问题:
#get height and width of image
height, width = possible_barcode_img.shape[:2]
#prepare list for rows
barcode_rows = []
for i in range(height):
# set variables and list for beginning of row
white_bar_width = 0
black_bar_width = 0
barcode_row = []
for j in range(width):
if possible_barcode_img[i,j] == 0:
#add to count
black_bar_width = black_bar_width +1
#ensure last bar is gotten if there was one
if white_bar_width > 0:
#add bar to row
barcode_row.append(["white", white_bar_width])
white_bar_width = 0
elif possible_barcode_img[i,j] > 0:
#add to width
white_bar_width = white_bar_width +1
#ensure last bar is gotten if there was one
if black_bar_width > 0:
#add bar to row
barcode_row.append(["black", black_bar_width])
black_bar_width = 0
#ensure last bar is gotten since a row just finished
if white_bar_width > 0:
#add bar to row
barcode_row.append(["white", white_bar_width])
elif black_bar_width > 0:
#add bar to row
barcode_row.append(["black", black_bar_width])
#add entire row to rows
barcode_rows.append(barcode_row)
打印问题print(barcode_rows[50])
中图片的第50行:
[['black', 3], ['white', 7], ['black', 4], ['white', 6], ['black', 4], ['white', 6], ['black', 13], ['white', 5], ['black', 4], ['white', 15], ['black', 4], ['white', 5], ['black', 5], ['white', 5], ['black', 13], ['white', 15], ['black', 13], ['white', 5], ['black', 13], ['white', 6], ['black', 3], ['white', 15], ['black', 5], ['white', 4], ['black', 4], ['white', 14], ['black', 13], ['white', 6], ['black', 4], ['white', 14], ['black', 13], ['white', 14], ['black', 5], ['white', 5], ['black', 4], ['white', 5], ['black', 4], ['white', 14], ['black', 4], ['white', 5], ['black', 4], ['white', 5], ['black', 13], ['white', 14], ['black', 13], ['white', 5], ['black', 14], ['white', 4], ['black', 5], ['white', 4]]
在图片中找到50条,准备解码。
如果其他人知道更快的方法会很有帮助。