Question

我想问用户三个问题

今天你高兴还是难过？
你矮还是高
你是强者还是弱者

作为调查的输出，我想将其结果显示为带有标点符号的句子以及针对用户的单个推荐（如果选择，请使用复合词）。

这是我到目前为止所拥有的：

 public static void main(String[] args) {

  String reply;
  String reply2;
  String reply3;

 Scanner scan = new Scanner(System.in); 
 System.out.println("Are you happy or sad today?");
  reply = scan.nextLine(); //Waits for input

  System.out.println("Are you short or tall");
    reply2 = scan.nextLine();

    System.out.println("Are you strong or weak");
    reply3 = scan.nextLine();

    if (reply.equalsIgnoreCase("Happy") && reply2.equalsIgnoreCase("Weak")&& reply3.equalsIgnoreCase("Short") ){
        System.out.println("You are a short happy person who is weak: I suggest more exercise ");

    }else if (reply.equalsIgnoreCase("sad") && reply2.equalsIgnoreCase("strong")&& reply3.equalsIgnoreCase("tall") ){
      System.out.println("You are a sad strong person who is tall: I suggest hugging a tree");

} else {
      System.out.println("Incorrect!" );
 }
}
}

我需要帮助弄清楚如何使用while-loop来提出问题，并且我的代码需要清理。

发布反馈：

package javaapplication13;



public static void main(String[] args) {

  String reply;
  String reply2;
  String reply3;

 Scanner scan = new Scanner(System.in); 
 do {
 System.out.println("Are you happy or sad today?");
  reply = scan.nextLine(); //Waits for input
 } while (!(reply.equalsIgnoreCase("happy") || reply.equalsIgnoreCase("sad")));

 do {
  System.out.println("Are you short or tall?");
    reply2 = scan.nextLine();
 } while (!(reply2.equalsIgnoreCase("short") || reply2.equalsIgnoreCase("tall")));


 do{ 
 System.out.println("Are you strong or weak");
    reply3 = scan.nextLine();
   } while (!(reply3.equalsIgnoreCase("strong") || reply3.equalsIgnoreCase("weak")));


 if (reply.equalsIgnoreCase("Happy") && reply2.equalsIgnoreCase("short")&& reply3.equalsIgnoreCase("weak") ){
        System.out.println("You are a short happy person who is weak: I suggest more exercise! ");


 } else if (reply.equalsIgnoreCase("sad") && reply2.equalsIgnoreCase("tall")&& reply3.equalsIgnoreCase("strong") ){
      System.out.println("You are a sad strong person who is tall: I suggest hugging a tree!");

      } else if (reply.equalsIgnoreCase("sad") && reply2.equalsIgnoreCase("short")&& reply3.equalsIgnoreCase("weak") ){
      System.out.println("You are a sad short person who is weak: I am sorry to hear that");





 }
}

}

Answer 1

由于您已经弄清楚了如何使用while循环，在代码中添加3个布尔值变量，分别代表情绪，身高和力量，这将使代码有所整理。

    boolean emotion;
    boolean height;
    boolean strength;

在do-while循环中，如果reply匹配“ Happy”，则将布尔值设置为true，否则将其设置为false，这显然会是“ sad”。其他两个问题也一样。

do {
        System.out.println("Are you happy or sad today?");
        reply = scan.nextLine(); // Waits for input
        if (reply.equalsIgnoreCase("Happy")) {
            emotion = true;
        } else {
            emotion = false;
        }
    } while (!(reply.equalsIgnoreCase("happy") || reply.equalsIgnoreCase("sad")));

    do {
        System.out.println("Are you short or tall?");
        reply2 = scan.nextLine();
        if (reply.equalsIgnoreCase("Tall")) {
            height = true;
        } else {
            height = false;
        }
    } while (!(reply2.equalsIgnoreCase("short") || reply2.equalsIgnoreCase("tall")));

    do {
        System.out.println("Are you strong or weak");
        reply3 = scan.nextLine();
        if (reply.equalsIgnoreCase("Strong")) {
            strength = true;
        } else {
            strength = false;
        }
    } while (!(reply3.equalsIgnoreCase("strong") || reply3.equalsIgnoreCase("weak")))

然后，当涉及到最后一部分时，您必须考虑3个答案的组合，而不需要编写像

这样的长代码

if(reply.equalsIgnoreCase("Happy") && reply2.equalsIgnoreCase("short")&& reply3.equalsIgnoreCase("weak"))

您只需检查布尔值即可确定您的建议。

if (emotion && !height && !strength) {
        System.out.println("You are a short happy person who is weak: I suggest more exercise! ");

    } else if (!emotion&&strength&&height) {
        System.out.println("You are a sad strong person who is tall: I suggest hugging a tree!");

    } else if (!emotion&&!height&&!strength) {
        System.out.println("You are a sad short person who is weak: I am sorry to hear that");

    }

Answer 2

为便于维护，请更好地利用Java集合。

2*inputSize - 1

如何使用一系列的while循环来询问用户问题？

2 个答案: