我正在用golang计算日期差,我已经写了代码并且执行得很好,但是当我以分钟为单位计算时间差时,将其转换为整数并在if条件下进行比较。
正在尝试的代码
根据以下条件,它不应打印“ diffinmin更大 P”,但它正在打印。我在哪里做错了?
package main
import (
"fmt"
"time"
"strconv"
)
func main() {
//fetching current time
currentTime := time.Now()
loc := currentTime.Location()
//past time comes in as string
pasttimestr := "2018-10-18 01:00"
layout := "2006-01-02 15:04"
//converting string to date
pasttime, err := time.ParseInLocation(layout, pasttimestr, loc)
if err != nil {
fmt.Println(err)
}
fmt.Println("Past Time: ", pasttime)
fmt.Println("Current Time: ", currentTime)
//differnce between pastdate and current date
diff := currentTime.Sub(pasttime)
var diffinmin int = int(diff.Minutes())
fmt.Printf( "heloo",diffinmin )
fmt.Printf("time difference is %v or %v in minutes\n", diff, diff.Minutes())
var strconfigtime = "9000"
var mininttimeconfig int
if mininttimeconfig, err := strconv.Atoi(strconfigtime); err == nil {
fmt.Printf("i=%d, type: %T\n", mininttimeconfig, mininttimeconfig)
}
if diffinmin > mininttimeconfig {
fmt.Printf("diffinmin is greater" )
}
}
答案 0 :(得分:2)
这与范围界定有关,您在检查中使用的mininttimeconfig的值为0。
if mininttimeconfig, err := strconv.Atoi(strconfigtime); err == nil {
// mininttimeconfig is a new variable scoped to this block
}
// here mininttimeconfig is 0 from declaration line
// var mininttimeconfig int
尝试将行更改为:
var mininttimeconfig int
mininttimeconfig, err = strconv.Atoi(strconfigtime);
if err == nil {
// ...
或者:
mininttimeconfig, err := strconv.Atoi(strconfigtime);
if err == nil {
// ...
请注意,通常使用错误,例如err!= nil {...}