Question

骰子的输出是随机的，为此我创建了一个函数。我想记录一次使骰子大于骰子2两次所花费的“尝试次数”。因此，当连续两次放大时，我希望将其打印出来（“花了+尝试+“使d1连续两次大于d2”）。到目前为止，我有这个但被卡住了：

public static int Dice() {
  return (int)(Math.random() * 6.0) + 1;
}

public static void main(String[] args) {

              int d1 = Dice();
              int d2 = Dice();
              int trials = 0;

              for (int i = 0; i < 100000; i++) {
               if (t1 > t2) {
               trials++;
               if (t1 > t2) {
                trials++ 
               }
              }
             }

            System.out.println(trials);
    } 
}

Answer 1

执行以下操作（将以下内容作为伪代码处理）：

public static int[] Dice() {
    int[] diceThrownTwoTimes = new int[2];
    diceThrownTwoTimes[0] = (int)(Math.random() * 6.0) + 1;
    diceThrownTwoTimes[1] = (int)(Math.random() * 6.0) + 1;
    return diceThrownTwoTimes;
} 

public static void main(String[] args) {
    int trials = 0;

    for (int i = 0; i < 100000; i++) {
        int[] d1 = Dice();
        int[] d2 = Dice();
        if (d1[0] > d2[0] && d1[1] > d2[1]) {
            trials++;
        }
    }
    System.out.println(trials);
}

编辑：

要获得两次连续两次大于dice1值的尝试，可以执行以下操作：

public static int[] Dice() {
    int[] diceThrownTwoTimes = new int[2];
    diceThrownTwoTimes[0] = (int)(Math.random() * 6.0) + 1;
    diceThrownTwoTimes[1] = (int)(Math.random() * 6.0) + 1;
    return diceThrownTwoTimes;
} 

public static void main(String[] args) {
    int trials = 0;

    for (int i = 0; i < 100000; i++) {
        int[] d1 = Dice();
        int[] d2 = Dice();
        if (d1[0] > d2[0] && d1[1] > d2[1]) {
            break;
        }else{
            trials++;
        }
    }
    System.out.println(trials);
}

Answer 2

我愿意

public static int Dice() {
  return (int)(Math.random() * 6.0) + 1;
}

public static void main(String[] args) {
  int trials = 0;
  int count = 0;

  while (count < 2) {
    int d1 = Dice();
    int d2 = Dice();

    if (d1 > d2) {
      ++count;
    } else {
      count = 0;
    }

    ++trials;
  }

  println("It took " + trials + " trials for d1 to be larger than d2 " + count + " times in a row.")
}

Answer 3

欢迎您！这应该工作。请参阅注释，以了解您做错了一些事情以及一些解释。

public static int Dice() {
  return (int)(Math.random() * 6.0) + 1;
}

public static void main(String[] args) {

  // initialize variables to be updated in the loop
  int trials = 0;
  Boolean lastTimeD1WasGreater = false;

  for (int i = 0; i < 100000; i++) {
    // always increment the counter!
    trials++;

    // you had the wrong variable names here.
    // also they must be INSIDE the loop or else they would always come out the same
    int d1 = Dice();
    int d2 = Dice();

    if (d1 > d2) {
      if (lastTimeD1WasGreater) {
        // if it was greater both last time and this time then we're done!
        System.out.println("it took " + trials + " trials.");
        break;
      } else {
        // otherwise set this variable so we can be on the lookout next time.
        lastTimeD1WasGreater = true;
      }
    } else {
      // d1 was not greater, so we'll start looking for a pair in the next loop.
      lastTimeD1WasGreater = false;
    }
  }
}

Answer 4

除非需要使用外部函数返回随机数，否则您可以在main函数中轻松完成此操作。

add_action( 'woocommerce_after_shop_loop_item', 'show_sale_percentage', 25 );

function show_sale_percentage() {

global $product;

if ( $product->is_on_sale() ) {

if ( ! $product->is_type( 'variable' ) ) {

$max_percentage = ( ( $product->get_regular_price() - $product->get_sale_price() ) / $product->get_regular_price() ) * 100;

} else {

$max_percentage = 0;

foreach ( $product->get_children() as $child_id ) {
$variation = wc_get_product( $child_id );
$price = $variation->get_regular_price();
$sale = $variation->get_sale_price();
if ( $price != 0 && ! empty( $sale ) ) $percentage = ( $price - $sale ) / $price * 100;
if ( $percentage > $max_percentage ) {
    $max_percentage = $percentage;
}
}

}

echo "<div class='saved-sale'>-" . round($max_percentage) . "%</div>";

}
}

d1连续两次大于d2进行了7次试验

样本输出

Answer 5

这是我想出的

import java.util.Random;

公共班级主要{

public static int Dice() {
    return (int) (Math.random() * 6.0) + 1;
}

public static void main(String[] args) {
    Random rand = new Random();


    int trials = 0;
    int twoTimes = 0;

    do {
        int d1 = rand.nextInt(25) + 1;
        int d2 = rand.nextInt(25) + 1;
        trials++;
        if (d1 > d2) {
            twoTimes++;
            System.out.printf("%s time greater\nd1 was " + d1 + "\nd2 was " + d2 + "\n-------\n", twoTimes);
        }
    }

    while (twoTimes != 2);
    System.out.printf("\nIt took %s times", trials);

}

}

在Java中滚动两个骰子，直到dice1大于dice2两次

5 个答案: