正则表达式找到最小长度的匹配项？

Question

THE (HIGH COURT OF HIMACHAL PRADESH)/ORG, (SHIMLA)/PLACE (Criminal
Appeal No. 235 of 2006)/CASE Judgment Reserved on : (27. 04. 2016)/DATE
Date of Decision : (June 2, 2016)/DATE 


Regular expression 
re.findall(r'\((.*?)\)\/(DATE)', line)
returns two string 
First:
(HIGH COURT OF HIMACHAL PRADESH)/ORG, (SHIMLA)/PLACE (Criminal
Appeal No. 235 of 2006)/CASE Judgment Reserved on : (27. 04. 2016)/DATE

Second:
(June 2, 2016)/DATE

But my required output is
First:
(27. 04. 2016)/DATE

Second:
(June 2, 2016)/DATE

我希望'（'是我字符串的最后一个左括号，而不是第一个括号。另一种解决方法是，如果我反转字符串，则必须相应地更改正则表达式，但是我还需要一些其他方法而不反转字符串。