SQL筛选器值取决于同一列中的其他值

时间:2018-10-15 06:39:24

标签: sql impala

我有一个包含“时间”,“操作”和“值”列的数据库。我想根据其他操作过滤某些操作。 示例:

Time    Action              Value
1:30    Drink sold          5
1:31    Happy hour          1
1:32    Drink sold          5 *
1:33    Happy hour          1
1:34    Drink sold          5 *
1:35    Drink sold          5 *
1:36    Drink sold          5 *
1:37    Happy hour          0
1:38    Drink sold          5
1:39    Drink sold          5
1:40    Drink sold          5
1:41    Happy hour          0
1:42    Drink sold          5
1:43    Happy hour          1
1:44    Drink sold          5 *
1:45    Happy hour          1
1:46    Drink sold          5 *
1:47    Drink sold          5 *
1:48    Drink sold          5 *
1:49    Happy hour          0
1:50    Drink sold          5

结果仅包含欢乐时光为1时售出的饮料。标有*。欢乐时光可以反复设置。 该数据库为,但理想情况下,解决方案仅使用普通SQL。

1 个答案:

答案 0 :(得分:0)

一种方法使用lag()将最近的行与欢乐时光记录进行比较。然后,只需考虑最近的值在哪里“ 1”:

select t.*
from (select t.*,
             max(case when action = 'Happy hour' and value = 0 then time end) over (order by time) as happy_hour_0,
             max(case when action = 'Happy hour' and value = 1 then time end) over (order by time) as happy_hour_1
      from t
     ) t
where action = 'Drink sold' and
      ((happy_hour_0 is null and happy_hour_1 is not null) or
       (happy_hour_1 > happy_hour_0)
      );