我有一张类似的表:
Index Name Type
--------------------------------
1 'Apple' 'Fruit'
2 'Carrot' 'Vegetable'
3 'Orange' 'Fruit'
3 'Mango' 'Fruit'
4 'Potato' 'Vegetable'
并希望将其更改为:
Index Name Type
--------------------------------
1 'Apple' 'Fruit 1'
2 'Carrot' 'Vegetable 1'
3 'Orange' 'Fruit 2'
3 'Mango' 'Fruit 3'
4 'Potato' 'Vegetable 2'
是否有机会在智能更新查询中执行此操作( =没有游标)?
答案 0 :(得分:3)
您可以使用update
运行join
以获取每行[type]
组中的row_number()
,然后使用[type]
将此值与[index]
连接起来}作为胶柱:
update t1 set t1.[type] = t1.[type] + ' ' + cast(t2.[rn] as varchar(3))
from [tbl] t1
join ( select [index]
, row_number() over (partition by [type] order by [index]) as [rn]
from [tbl]
) t2 on t1.[index] = t2.[index]
答案 1 :(得分:0)
假设您的表有一个名为ID的主键,那么您可以运行以下命令:
update fruits
set Type = newType
from
(
select f.id
,f.[index]
,f.Name
,f.[Type]
,Type + ' '+ cast((select COUNT(*)
from fruits
where Type = f.Type
and Fruits.id <= f.id) as varchar(10)) as newType
from fruits f
) t
where t.id = fruits.id
答案 2 :(得分:0)
SELECT Index ,Name, Type, ROW_NUMBER() OVER (PARTITION BY Type ORDER BY Index)AS RowNum
INTO #temp
FROM table_name
UPDATE #temp
SET Type = Type + ' ' + CAST(RowNum AS NVARCHAR(15))
UPDATE table_name
SET Type = t2.Type
FROM table_name t1
JOIN #temp t2 ON t2.Index = t1.Index
答案 3 :(得分:0)
您可以使用以下事实:您可以更新cte:
false