Question

我正在将Entry窗口小部件StringVal传递给一个函数，该函数在另一个模块中查找您键入的内容。即a1 =123456。当我在Entry小部件中键入“ a1”时，我的函数仅返回“ a1”，而不返回其对应的值“ 123456”。我不知道如何获取def用户函数来将标签配置为123456而不是a1。

from tkinter import *

class App(Frame):
    def __init__(self, master):
        super(App, self).__init__(master)
        self.grid()
        self.create_widgets()

    def create_widgets(self):
        a1 = 123456
        a2 = 456789
        a3 = 789456

        self.Userin = StringVar()

        self.user_input = Entry(self, insertwidth=0, width=30,
        textvariable=self.Userin)
        self.user_input.grid(row=2)
        self.user_input.insert(0, "0")

        self.bttn1 = Button(self, padx = 15, pady = 15, text = "Call A1",
        command = lambda: self.getdata(a1))
        self.bttn1.grid(row = 0, column = 0)

        self.bttn2 = Button(self, padx=15, pady=15, text="Call your entry",
        command=lambda: self.userd(self.Userin.get()))
        self.bttn2.grid(row=0, column=1)

        self.label = Label(self,bg = "white", padx = 35, pady = 25, text = "***")
        self.label.grid(row = 1)

    def userd(self,xxx):          
        self.label.configure(text = xxx)

    def getdata(self,row):
        self.label.configure(text = row)

root = Tk()
root.geometry("300x150")
App(root)
root.mainloop()

Answer 1

您的代码可以正常工作。您的函数返回“ a1”，因为您从不编写其他任何代码。

添加如下条件：

from tkinter import *

class App(Frame):
    def __init__(self, master):
        super(App, self).__init__(master)
        self.grid()
        self.create_widgets()

    def create_widgets(self):
        self.a1 = 123456
        self.a2 = 456789
        self.a3 = 789456

        self.Userin = StringVar()

        self.user_input = Entry(self, insertwidth=0, width=30,
        textvariable=self.Userin)
        self.user_input.grid(row=2)
        self.user_input.insert(0, "0")

        self.bttn1 = Button(self, padx = 15, pady = 15, text = "Call A1",
        command = lambda: self.getdata(self.a1))
        self.bttn1.grid(row = 0, column = 0)

        self.bttn2 = Button(self, padx=15, pady=15, text="Call your entry",
        command=lambda: self.userd(self.Userin.get()))
        self.bttn2.grid(row=0, column=1)

        self.label = Label(self,bg = "white", padx = 35, pady = 25, text = "***")
        self.label.grid(row = 1)

    def userd(self,xxx):
        if xxx == "a1":
            self.label.configure(text = self.a1)
        elif xxx == "a2":
            self.label.configure(text = self.a2)
        elif xxx == "a3":
            self.label.configure(text = self.a3)

    def getdata(self,row):
        self.label.configure(text = row)

root = Tk()
root.geometry("300x150")
App(root)
root.mainloop()

Entry Widget在函数中无法正常工作以调用另一个模块

1 个答案: