Question

我必须遵循有效的代码，但不是我想要的代码

if(isset($_POST['edit']) && $_POST['edit']!="")
{
    // Email Information
    $firstName = $_POST['fname'];
    $lastName = $_POST['lname'];
    $mobile = $_POST['contactNumber'];
    $comments = $_POST['message'];
    $email_from = $_POST['email'];
    $email_to = "info@munsterweddingdjs.com";
    //$email_headers = "From: ". $firstName ." ". $lastName . " <" . $email_from . ">\r\n" . "Reply-To: info@munsterweddingdjs.com";
    $email_headers = "From: $firstName $lastName <kevin@yourwebsite.com>" . "\r\n" . "Reply-To: info@munsterweddingdjs.com";


    $email_subject = "Munster Wedding DJs Inquiry!";
    $email_body = "\nName: " . $firstName . " " . $lastName .
    "\nEmail: " . $email_from . 
    "\nPhone Number: " . $mobile . 
    "\nMessage: " . $comments;

    // Send Email
    $mailerResult = @mail($email_to, "$email_subject", $email_body,
    $email_headers, '-f ' . $email_from);

    // Check For Errors
    if($mailerResult) {

        //echo "Mail Sent!";
        echo '<script>document.location.href="thanks.html#anchor"</script>';
        exit();

    } else {

        //  echo "Error Sending Email!" . "<br><br>";
        //  print_r(error_get_last());
    }

}

如果我改变

From: $firstName $lastName <kevin@yourwebsite.com>"

到

From: $firstName $lastName <$email_from>"

表格没有发送电子邮件？这是为什么？

我想要做的就是接收电子邮件，当我点击回复时，它会将用户的电子邮件地址放入＆＃34; to＆＃34;字段。

Answer 1

尝试使用这样的， ＆amp; lt; for＆lt; ＆strong;＆gt;

的＆amp; gt;

删除＆amp; lt 和;

之间的空格

$email_headers = "From: $firstName $lastName &lt; $email_from &gt;" . "\r\n" . "Reply-To: info@munsterweddingdjs.com";

mail（）函数无法正常工作

1 个答案: