Question

我正在尝试使我的简单C＃图形库多线程化。但是，在引入此代码之后：

/* foreach (IAffector affector in affectorLookup.Values)
    affector.Update(timestep); */

taskManager.Value = timestep; taskManager.Start();

foreach (IAffector affector in affectorLookup.Values)
    taskManager.AddToQueue(affector.Update);
taskManager.StopWhenDone();
taskManager.Wait();

模拟开始出现严重的滞后尖峰，这似乎起源于TaskHandler.Run（我无法确定，因为添加前面的代码会使我的代码分析器忽略TaskHandler.Run之外的任何内容）。

任务经理：

public class TaskManager
{
    public delegate void MethodDel(float timestep);
    private Queue<MethodDel> queue;
    private List<TaskHandler> handlers;
    private float value;


    public float Value
    {
        get
        {
            return value;
        }
        set
        {
            this.value = value;
        }
    }


    public TaskManager()
    {
        this.queue = new Queue<MethodDel>();
        this.handlers = new List<TaskHandler>(System.Environment.ProcessorCount);

        for (int t = 0; t < this.handlers.Capacity; ++t)
            this.handlers.Add(new TaskHandler(this));

        this.value = 0;
    }


    public void Start()
    {
        foreach (var handler in handlers)
            handler.Start();
    }


    public void Stop()
    {
        lock (queue)
            queue.Clear();

        foreach (var handler in handlers)
            handler.StopWhenDone();
    }


    public void StopWhenDone()
    {
        foreach (var handler in handlers)
            handler.StopWhenDone();
    }


    public void AddToQueue(MethodDel method)
    {
        lock (queue)
            queue.Enqueue(method);
    }


    public bool GetFromQueue(out MethodDel method)
    {
        lock (queue)
        {
            if (queue.Count == 0) { method = null; return false; }

            method = queue.Dequeue();
            return true;
        }
    }


    public int GetQueueCount()
    {
        return queue.Count;
    }

    internal void Wait()
    {
        // Have to wait for them one at a time because the main thread is STA.

        WaitHandle[] waitHandles = new WaitHandle[1];
        // for (int t = 0; t < handlers.Count; ++t)
            // waitHandles[t] = handlers[t].WaitHandle;

        // WaitHandle.WaitAll(waitHandles);
        for (int t = 0; t < handlers.Count; ++t)
        { waitHandles[0] = handlers[t].WaitHandle; WaitHandle.WaitAll(waitHandles); }
    }
}

任务处理程序：

public class TaskHandler
{
    private TaskManager manager;
    private Thread thread;
    private bool stopWhenDone;
    private ManualResetEvent waitHandle;


    public ManualResetEvent WaitHandle
    {
        get
        {
            return waitHandle;
        }
    }


    public TaskHandler(TaskManager manager)
    {
        this.manager = manager;
    }


    public void Start()
    {
        waitHandle = new ManualResetEvent(false);

        stopWhenDone = false;

        thread = new Thread(Run);
        thread.IsBackground = true;
        thread.SetApartmentState(ApartmentState.MTA);
        thread.Start();
    }


    public void StopWhenDone()
    {
        this.stopWhenDone = true;
    }

    // Possible source of slowdown
    private void Run()
    {
        TaskManager.MethodDel curMethod;
        while (!stopWhenDone || manager.GetQueueCount() > 0)
        {
            if (manager.GetFromQueue(out curMethod))
            {
                curMethod(manager.Value);
            }
        }
        waitHandle.Set();
    }
}

Answer 1

启动线程是一项繁重的操作。不确定它是否像您遇到的那样沉重，但可能就是这样。此外，让所有处理并行运行可能会对您的系统造成很大压力，而且可能带来的好处......

Answer 2

我打算冒险使用尖峰与waitHandle.Set（）;

我喜欢整体设计，但我之前没有使用过WaitHandle，所以我不确定它是如何与你的设计相互作用的。

多线程代码中频繁出现滞后峰值

2 个答案: