我有一个数据框“蠕虫”,我对计算平均值有两个感兴趣的因素-长度相同的“ worm.density”和“ Vegetation”。植被有5个数据框,我平均需要2个-“ Meadow”和“ Grassland”,同时还要插入一个条件,该条件仅包含Area> 2.5和Soil.Ph> 3.5因子的结果。是否可以通过轻触来做到这一点,或者循环是实现此目的的最佳方法?我卡住了,只能用我的植被因子限制两个数据帧。
从www.bio.ic.ac.uk/research/crawley/statistics / 下载的数据文件
worms<-structure(list(Field.Name = structure(c(8L, 17L, 10L, 16L, 7L,
11L, 3L, 1L, 19L, 15L, 5L, 9L, 18L, 12L, 13L, 20L, 2L, 14L, 6L,
4L), .Label = c("Ashurst", "Cheapside", "Church.Field", "Farm.Wood",
"Garden.Wood", "Gravel.Pit", "Gunness.Thicket", "Nashs.Field",
"North.Gravel", "Nursery.Field", "Oak.Mead", "Observatory.Ridge",
"Pond.Field", "Pound.Hill", "Rookery.Slope", "Rush.Meadow", "Silwood.Bottom",
"South.Gravel", "The.Orchard", "Water.Meadow"), class = "factor"),
Area = c(3.6, 5.1, 2.8, 2.4, 3.8, 3.1, 3.5, 2.1, 1.9, 1.5,
2.9, 3.3, 3.7, 1.8, 4.1, 3.9, 2.2, 4.4, 2.9, 0.8), Slope = c(11L,
2L, 3L, 5L, 0L, 2L, 3L, 0L, 0L, 4L, 10L, 1L, 2L, 6L, 0L,
0L, 8L, 2L, 1L, 10L), Vegetation = structure(c(2L, 1L, 2L,
3L, 5L, 2L, 2L, 1L, 4L, 2L, 5L, 2L, 2L, 2L, 3L, 3L, 5L, 1L,
2L, 5L), .Label = c("Arable", "Grassland", "Meadow", "Orchard",
"Scrub"), class = "factor"), Soil.pH = c(4.1, 5.2, 4.3, 4.9,
4.2, 3.9, 4.2, 4.8, 5.7, 5, 5.2, 4.1, 4, 3.8, 5, 4.9, 4.7,
4.5, 3.5, 5.1), Damp = c(FALSE, FALSE, FALSE, TRUE, FALSE,
FALSE, FALSE, FALSE, FALSE, TRUE, FALSE, FALSE, FALSE, FALSE,
TRUE, TRUE, TRUE, FALSE, FALSE, TRUE), Worm.density = c(4L,
7L, 2L, 5L, 6L, 2L, 3L, 4L, 9L, 7L, 8L, 1L, 2L, 0L, 6L, 8L,
4L, 5L, 1L, 3L)), class = "data.frame", row.names = c(NA,
-20L))
> with(worms,tapply(Worm.density,list[Grassland,Meadow],mean))
sessioninfo()R版本3.5.1(2018-07-02) 平台:x86_64-apple-darwin15.6.0(64位) 运行于:macOS Sierra 10.12.6
Matrix产品:默认 BLAS:/System/Library/Frameworks/Accelerate.framework/Versions/A/Frameworks/vecLib.framework/Versions/A/libBLAS.dylib LAPACK:/System/Library/Frameworks/Accelerate.framework/Versions/A/Frameworks/vecLib.framework/Versions/A/libLAPACK.dylib
语言环境: [1] C
附带的基本软件包: [1]统计图形grDevices utils数据集方法基础
其他附件包: [1] RevoUtils_11.0.1
通过名称空间(未附加)加载: [1]编译器_3.5.1工具_3.5.1
答案 0 :(得分:1)
简单地subset
tapply
中的{em>蠕虫数据帧就会产生一个命名向量:
with(subset(worms, Area > 2.5 & Soil.pH > 3.5),
tapply(Worm.density, Vegetation, mean)
)
# Arable Grassland Meadow Orchard Scrub
# 6.000000 2.333333 7.000000 NA 7.000000
要仅返回草原和草地,请用[]
with(subset(worms, Area > 2.5 & Soil.pH > 3.5),
tapply(Worm.density, Vegetation, mean)
)[c("Grassland", "Meadow")]
# Grassland Meadow
# 2.333333 7.000000
仅对于 Grassland 和 Meadow 类型均值,将其添加到子集中并取均值 Worm.density :
sub_worms <- subset(worms, Area > 2.5 & Soil.pH > 3.5 &
Vegetation %in% c("Grassland", "Meadow"))
sub_worms
# Field.Name Area Slope Vegetation Soil.pH Damp Worm.density
# 1 Nashs.Field 3.6 11 Grassland 4.1 FALSE 4
# 3 Nursery.Field 2.8 3 Grassland 4.3 FALSE 2
# 6 Oak.Mead 3.1 2 Grassland 3.9 FALSE 2
# 7 Church.Field 3.5 3 Grassland 4.2 FALSE 3
# 12 North.Gravel 3.3 1 Grassland 4.1 FALSE 1
# 13 South.Gravel 3.7 2 Grassland 4.0 FALSE 2
# 15 Pond.Field 4.1 0 Meadow 5.0 TRUE 6
# 16 Water.Meadow 3.9 0 Meadow 4.9 TRUE 8
mean(sub_worms$Worm.density)
# [1] 3.5