Question

有人可以告诉我错误在哪里吗？我已经绕了一个星期来解决这个问题。我收到错误 “ TypeError：列表索引必须是整数或切片，而不是列表” 表示要在播放器选择索引的位置放置“ X”的playerXturn（）函数中的代码行。

def main():
    gameBoard = [[" ", " ", " "],
                 [" ", " ", " "],
                 [" ", " ", " "]]

    printBoard(gameBoard)

    playerXturn(gameBoard)

    while boardFull(gameBoard) is False:

        if diagonalWin(gameBoard) is False and rowWin(gameBoard) is False:
            playerOturn(gameBoard)
            if diagonalWin(gameBoard) is False and rowWin(gameBoard) is False:
                playerXturn(gameBoard)
            else:
                print("Player X wins!")
        else:
            print("Player O wins!")

        printBoard(gameBoard)


def printBoard(gameBoard):
    print("---------")
    print(gameBoard[0][0], "|", gameBoard[0][1], "|", gameBoard[0][2])
    print("---------")
    print(gameBoard[1][0], "|", gameBoard[1][1], "|", gameBoard[1][2])
    print("---------")
    print(gameBoard[2][0], "|", gameBoard[2][1], "|", gameBoard[2][2])
    print("---------")


def playerXturn(gameBoard):
    playerXrowChoice = input("Enter a row (0, 1, or 2) for player X: ")
    playerXrow = [eval(x) for x in playerXrowChoice]
    playerXcolumnChoice = input("Enter a column (0, 1, or 2) for player X: ")
    playerXcolumn = [eval(x) for x in playerXcolumnChoice]

    if gameBoard[playerXrow][playerXcolumn] != "X" and gameBoard[playerXrow][playerXcolumn] != "O":
        gameBoard[playerXrow, playerXcolumn] = "X"
    else:
        print("This spot is already taken.")

    return gameBoard


def playerOturn(gameBoard):
    playerOrowChoice = input("Enter a row (0, 1, or 2) for player X: ")
    playerOrow = [eval(x) for x in playerOrowChoice]
    playerOcolumnChoice = input("Enter a column (0, 1, or 2) for player X: ")
    playerOcolumn = [eval(x) for x in playerOcolumnChoice]

    if gameBoard[playerXrow][playerXcolumn] != "X" and gameBoard[playerXrow][playerXcolumn] != "O":
        gameBoard[playerOrow, playerOcolumn] = "O"
    else:
        print("This spot is already taken.")

    return gameBoard

#check for empty spaces on the board
def boardFull(gameBoard):
    for i in range(len(gameBoard)):
        for j in range(len(gameBoard[i])):
            if j != " ":
                return True
            else:
                return False


#check for diagonal match
def diagonalWin(b):
    while b[1][1] != " ":
        if b[1][1] == b[0][0] == b[2][2] or b[1][1] == b[0][2] == b[2][0]:
            return True
        else:
            return False

#check for 3 in a row
def rowWin(b):
    for row in range(0, 3):
        if b[row][0] == b[row][1] == b[row][2] == 'X':
            return True
        else:
            return False

main()

Answer 1

错误在这一行：

gameBoard[playerXrow, playerXcolumn] = "X"

我想你的意思是

gameBoard[playerXrow][playerXcolumn] = "X"

Answer 2

我是python的新手，所以我不知道eval（）的作用，但是我弄清楚了错误在哪里。

def playerXturn(gameBoard):
playerXrowChoice= input("Enter a row (0, 1, or 2) for player X: ")
playerXrow = [eval(x) for x in playerXrowChoice]
playerXcolumnChoice= input("Enter a column (0, 1, or 2) for player X: ")
playerXcolumn = [eval(x) for x in playerXcolumnChoice]

if gameBoard[playerXrow][playerXcolumn] != "X" and gameBoard[playerXrow][playerXcolumn] != "O":
    gameBoard[playerXrow, playerXcolumn] = "X"
else:
    print("This spot is already taken.")

return gameBoard

在线：

gameBoard[playerOrow, playerOcolumn] = "X"

在这里，您需要定位一个特定的像这样的单元：在这种情况下，gameBoard [row] [column]：

gameBoard[playerOrow][playerOcolumn] = "X"

在更改之后我尝试运行代码，但又遇到了另一个错误，但我解决了。

正如我说的，我不知道是哪几行：

playerXcolumn = [eval(x) for x in playerXcolumnChoice]
playerXcolumn = [eval(x) for x in playerXcolumnChoice]

这样做是为了删除它们以及您要求用户输入的地方：

playerXrowChoice= input("Enter a row (0, 1, or 2) for player X: ")
playerXcolumnChoice= input("Enter a column (0, 1, or 2) for player X: ")

您需要将输入从字符串转换为int，以便您可以定位到GameBoard的正确单元格。

我的井字游戏出现我不理解的TypeError

2 个答案: