此代码是方法中的一部分。该代码使用两个for循环遍历两个列表。我想看看是否有可能使用多线程来加快两个循环的速度。我关心的是如何使它线程安全。
已编辑:更完整的代码
static class Similarity {
double similarity;
String seedWord;
String candidateWord;
public Similarity(double similarity, String seedWord, String candidateWord) {
this.similarity = similarity;
this.seedWord = seedWord;
this.candidateWord = candidateWord;
}
public double getSimilarity() {
return similarity;
}
public String getSeedWord() {
return seedWord;
}
public String getCandidateWord() {
return candidateWord;
}
}
static class SimilarityTask implements Callable<Similarity> {
Word2Vec vectors;
String seedWord;
String candidateWord;
Collection<String> label1;
Collection<String> label2;
public SimilarityTask(Word2Vec vectors, String seedWord, String candidateWord, Collection<String> label1, Collection<String> label2) {
this.vectors = vectors;
this.seedWord = seedWord;
this.candidateWord = candidateWord;
this.label1 = label1;
this.label2 = label2;
}
@Override
public Similarity call() {
double similarity = cosineSimForSentence(vectors, label1, label2);
return new Similarity(similarity, seedWord, candidateWord);
}
}
现在,此“计算”线程安全吗?涉及3个变量:
1) vectors;
2) toeknizerFactory;
3) similarities;
public static void compute() throws Exception {
File modelFile = new File("sim.bin");
Word2Vec vectors = WordVectorSerializer.readWord2VecModel(modelFile);
TokenizerFactory tokenizerFactory = new TokenizerFactory()
List<String> seedList = loadSeeds();
List<String> candidateList = loadCandidates();
log.info("Computing similarity: ");
ExecutorService POOL = Executors.newFixedThreadPool(Runtime.getRuntime().availableProcessors());
List<Future<Similarity>> tasks = new ArrayList<>();
int totalCount=0;
for (String seed : seedList) {
Collection<String> label1 = getTokens(seed.trim(), tokenizerFactory);
if (label1.isEmpty()) {
continue;
}
for (String candidate : candidateList) {
Collection<String> label2 = getTokens(candidate.trim(), tokenizerFactory);
if (label2.isEmpty()) {
continue;
}
Callable<Similarity> callable = new SimilarityTask(vectors, seed, candidate, label1, label2);
tasks.add(POOL.submit(callable));
log.info("TotalCount:" + (++totalCount));
}
}
Map<String, Set<String>> similarities = new HashMap<>();
int validCount = 0;
for (Future<Similarity> task : tasks) {
Similarity simi = task.get();
Double similarity = simi.getSimilarity();
String seedWord = simi.getSeedWord();
String candidateWord = simi.getCandidateWord();
Set<String> similarityWords = similarities.get(seedWord);
if (similarity >= 0.85) {
if (similarityWords == null) {
similarityWords = new HashSet<>();
}
similarityWords.add(candidateWord);
log.info(seedWord + " " + similarity + " " + candidateWord);
log.info("ValidCount: " + (++validCount));
}
if (similarityWords != null) {
similarities.put(seedWord, similarityWords);
}
}
}
添加了另一种相关方法,供call()方法使用:
public static double cosineSimForSentence(Word2Vec vectors, Collection<String> label1, Collection<String> label2) {
try {
return Transforms.cosineSim(vectors.getWordVectorsMean(label1), vector.getWordVectorsMean(label2));
} catch (Exception e) {
log.warn("OOV: " + label1.toString() + " " + label2.toString());
//e.getMessage();
//e.printStackTrace();
return 0.0;
}
}
答案 0 :(得分:0)
(已更新问题的答案。)
通常,在尝试优化代码之前,应对它进行概要分析,尤其是在代码非常复杂的情况下。
对于线程,您需要确定线程之间共享的可变状态。理想情况下,在求助于锁和并发数据结构之前,应尽可能地多。这样,一个线程中包含的可变状态就不是问题。不变的东西很棒。
我认为传递给您的任务的任何内容都不会修改。很难说。在字段上使用final
是个好主意。可以将集合放置在不可修改的包装中,尽管这并不能阻止它们通过其他引用进行修改,并且现在可以以静态类型显示。
假设您不破坏内部循环,则唯一的共享可变状态似乎是similarities
及其包含的值。
您可能会或可能不会发现您最终仍然做过多的串行操作,需要更改similarities
才能并发
ConcurrentMap<String, Set<String>> similarities = new ConcurrentHashMap<>();
get
中的put
和similarities
必须是线程安全的。我建议始终创建Set
。
Set<String> similarityWords = similarities.getOrDefault(seed, new HashSet<>());
或
Set<String> similarityWords = similarities.computeIfAbsent(seed, key -> new HashSet<>());
您可以使用线程安全的Set
(例如,使用Collections.synchronizedSet
),但是我建议为整个内部循环持有一个相关的锁。
synchronized (similarityWords) {
...
}
如果您想懒惰地创建similarityWords
,那将是“更加有趣”。