如何使用Angular 5验证电子邮件

时间:2018-10-03 12:57:05

标签: javascript html angular typescript

我想知道如何使用.com验证电子邮件 我尝试了一切,但我不能,您能帮我吗? 我正在包装已经开发的代码,这是我的新手,并且发现在此主题上很难。 如果用户键入.com,我希望对电子邮件进行验证,但直到现在我仅获得基本验证,例如:example @ example。 我希望它是example@example.com

谢谢

  

.ts

   import { ActivatedRoute, Params, Router } from "@angular/router";
import { Component, OnInit, Inject, } from '@angular/core';
import { FormControl, Validators, FormGroup, FormBuilder } from '@angular/forms';
import { Observable, Subscription } from "rxjs";
import { ModelDataForm } from "./modelDataForm";
import { DOCUMENT } from "@angular/platform-browser";
import 'rxjs/add/operator/filter'

@Component({
  selector: 'app-root',
  templateUrl: './app.component.html',
  styleUrls: ['./app.component.css']
})



export class AppComponent implements OnInit {

  userService: any;
  isTCAccepted: any;
  private subscription: Subscription;
  uri: string;
  ssid: string;
  sessiondId: string;
  ip: string;
  mac: string;
  ufi: string;
  mgmtBaseUrl: string;
  clientRedirectUrl: string;
  req: string;
  userName: string;
  hmac: string;

  name: string;
  email: string;

  //checkbox
  isValidFormSubmitted: boolean = null;




  constructor(@Inject(DOCUMENT) private document: any, private route: ActivatedRoute) {
  }

  //checkbox
  onFormSubmit() {
    this.isValidFormSubmitted = false;
    if (this.userForm.invalid) {
      return;
    }
    this.isValidFormSubmitted = true;
    this.isTCAccepted = this.userForm.get('tc').value;

  }


  ngOnInit() {
    this.route.queryParams
      .filter(params => params.mac)
      .subscribe(params => {
        console.log(params);

        this.ssid = params.ssid;
        this.sessiondId = params.sessionId;
        this.ip = params.ip;
        this.mac = params.mac;
        this.ufi = params.ufi;
        this.mgmtBaseUrl = params.mgmtBaseUrl;
        this.clientRedirectUrl = params.clientRedirectUrl;
        this.req = params.req;
        this.hmac = params.hmac;
      });
  }



  emailFormControl = new FormControl('', [
    Validators.required,
    Validators.pattern('[a-zA-Z0-9.-_]{1,}@[a-zA-Z.-]{2,}[.]{1}[a-zA-Z]{2,}'),
    Validators.email,
  ]);

  nameFormControl = new FormControl('', [
    Validators.required,
  ]);



  userForm = new FormGroup({
    tc: new FormControl('', [(control) => {
      return !control.value ? { 'required': true } : null;
    }])
  });

}
  

html

<mat-form-field class="hcs-full-width">

  <input matInput placeholder="Nome" [formControl]="nameFormControl" [(ngModel)]="name">
  <mat-error *ngIf="nameFormControl.hasError('required')">
    Nome é
    <strong>requirido</strong>
  </mat-error>
</mat-form-field>


<mat-form-field class="hcs-full-width">
  <input matInput  placeholder="E-mail" [formControl]="emailFormControl" [(ngModel)]="email" >
  <mat-error *ngIf="emailFormControl.hasError('email') && !emailFormControl.hasError('required') && !emailFormControl.hasError('pattern')">
    Por favor entre com um endereço de e-mail valido
  </mat-error>
  <mat-error *ngIf="emailFormControl.hasError('required')">
    E-mail é
    <strong>requirido</strong>
  </mat-error>
</mat-form-field>

<br>

<div class="checkbox">
  <mat-checkbox class="hcs-full-width" formControlName="tc">
  </mat-checkbox>
  Aceito os termos e condições de uso
  <a data-toggle="collapse" href="#collapseExample">
    ver os termos
  </a>
</div>
<mat-error *ngIf="userForm.get('tc').invalid && isValidFormSubmitted != null && !isValidFormSubmitted" [ngClass]="'error'">
  É necessário aceitar os termos de uso
</mat-error>


<br>

<button mat-button type="submit" class="btn btn-primary btn-lg btn-block button-size" (click)="Logar()">Enviar</button>

<div class="space"></div>

6 个答案:

答案 0 :(得分:0)

尝试一下,我们可以使用正则表达式模式进行验证

<input type="email" [(ngModel)]="enterEmail" name="myEmail" 
#myEmail="ngModel" email pattern="[a-zA-Z0-9.-_]{1,}@[a-zA-Z.-]{2,}[.]{1}[a-zA-Z]{2,}" required>

答案 1 :(得分:0)

您需要更改模式,请在电子邮件ID中使用波纹管模式。

有效电子邮件ID的示例:

sample@sam.com-有效, sample@sam.in-有效, sample @ sam-邀请。

pattern="^\w+([\.-]?\w+)*@\w+([\.-]?\w+)*(\.\w{2,3})+$"

答案 2 :(得分:0)

尝试正则表达式

emailFormControl: new FormControl('', Validators.compose([Validators.required, Validators.pattern(/^(([^<>()\[\]\\.,;:\s@"]+(\.[^<>()\[\]\\.,;:\s@"]+)*)|(".+"))@((\[[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\])|(([a-zA-Z\-0-9]+\.)+[a-zA-Z]{2,}))$/)])),

答案 3 :(得分:0)

 Either you can user HTML5 type attribute as email like type="email"
            <div class="form-group">
              <input class="form-control text-sm-x2 pl-5" placeholder="Email Id" type="email" name="email" [(ngModel)]="userCredentials.email"
                [disabled]="disableInputs" required email #email="ngModel">
              <span class="help-block" *ngIf="email?.dirty && email?.errors?.email" style="color:red">
                <small>Enter a valid email</small>
              </span>
            </div>
  OR
use pattern attribute like:
pattern="^[a-z0-9._%+-]+@[a-z0-9.-]+\.[a-z]{2,4}$" with default type="text".

答案 4 :(得分:0)

尝试这个简单的正则表达式

if (emailString.match(/[A-Za-z0-9!#$%&'*+/=?^_`{|}~-]+(?:\.[A-Za-z0-9!#$%&'*+/=?^_`{|}~-]+)*@(?:[a-z0-9A-Z](?:[a-z0-9A-Z]*[a-z0-9A-Z])?\.)+[a-z0-9A-Z](?:[a-z0-9A-Z]*[a-z0-9A-Z])?/)) {
    return null;
  } else {
    return { 'invalidEmailAddress': true };
  }

检查此Stackblitz示例 demo

答案 5 :(得分:0)

首选Angular提供的电子邮件验证程序。

<input type="email" name="email" ngModel email>
<input type="email" name="email" ngModel email="true">
<input type="email" name="email" ngModel [email]="true">

参考:

  1. https://angular.io/api/forms/EmailValidator