我想验证电子邮件域,但我不想担心可能出现的任何可能的子域。
例如:
@abc.com
@a.abc.com
@b.abc.com
...
这些都应该有效。
另外,我有一个要验证的域名列表,例如abc.com,xyz.com ......如何从列表中验证电子邮件域名,包括子域名?
感谢。
答案 0 :(得分:2)
您还可以使用dns验证域名:
function validEmail($email)
{
$allowedDomains = array('abc.com');
list($user, $domain) = explode('@', $email);
if (checkdnsrr($domain, 'MX') && in_array($domain, $allowedDomains))
{
return true;
}
return false;
}
答案 1 :(得分:1)
我前一段时间写了这个函数。它可能满足您所寻找的要求。它做了两件事,验证电子邮件地址是有效地址,然后验证域名是否是DNS中的有效名称。
function validate_email($email) {
// Check email syntax
if(preg_match('/^([a-zA-Z0-9\._\+-]+)\@((\[?)[a-zA-Z0-9\-\.]+\.([a-zA-Z]{2,7}|[0-9]{1,3})(\]?))$/', $email, $matches)) {
$user = $matches[1];
$domain = $matches[2];
// Check availability of DNS MX records
if(getmxrr($domain, $mxhosts, $mxweight)) {
for($i=0;$i<count($mxhosts);$i++){
$mxs[$mxhosts[$i]] = $mxweight[$i];
}
// Sort the records
asort($mxs);
$mailers = array_keys($mxs);
} elseif(checkdnsrr($domain, 'A')) {
$mailers[0] = gethostbyname($domain);
} else {
$mailers = array();
}
$total = count($mailers);
// Added to still catch domains with no MX records
if($total == 0 || !$total) {
$error = "No MX record found for the domain.";
}
} else {
$error = "Address syntax not correct.";
}
return ($error ? $error : TRUE);
}
答案 2 :(得分:1)
我决定将其重写为更加友好,这样您就不会受限于白名单的域名方案类型。
$whitelist = array("abc.com", "xyz.com", "specific.subdomain.com", "really.specific.subdomain.com"); //You can add basically whatever you want here because it checks for one of these strings to be at the end of the $email string.
$email = "@d.xyz.com";
function validateEmailDomain($email, $domains) {
foreach ($domains as $domain) {
$pos = strpos($email, $domain, strlen($email) - strlen($domain));
if ($pos === false)
continue;
if ($pos == 0 || $email[(int) $pos - 1] == "@" || $email[(int) $pos - 1] == ".")
return true;
}
return false;
}
所以,你可以使用它:
if (validateEmailDomain($email, $whitelist))
//Do something.
答案 3 :(得分:1)
我写了一个简单的正则表达式示例,可以检查域列表。
<?php
$email = 'shagtv@a.xyz.com';
$domains = array('abc.com', 'xyz.com');
$pattern = "/^[a-z0-9._%+-]+@[a-z0-9.-]*(" . implode('|', $domains) . ")$/i";
if (preg_match($pattern, $email)) {
echo 'valid';
} else {
echo 'not valid';
}
?>
答案 4 :(得分:0)
你应该使用这样的代码:
<?php
$subject = "abcdef";
$pattern = '/^def/';
preg_match($pattern, substr($subject,3), $matches, PREG_OFFSET_CAPTURE);
print_r($matches);
?>
或者这个:
<?php
$email = "someone@exa mple.com";
if(!filter_var($email, FILTER_VALIDATE_EMAIL))
{
echo "E-mail is not valid";
}
else
{
echo "E-mail is valid";
}
?>
或this that you have to do a little modify与this page。
希望它有所帮助!
答案 5 :(得分:0)
与此帖非常相似:PHP Check domain of email being registered is a 'school.edu' address
但是,您需要更进一步。完成拆分后,请查看parse_url http://php.net/manual/en/function.parse-url.php抓住主机部分。