我打算将“ Jan 2009”字符串转换为日期。但是，我遇到以下给定的错误。
AsDate("Jun 2009")
Error in regexec(patt, x1, perl = TRUE, ignore.case = TRUE) :
unused argument (perl = TRUE)
我的会话信息保持不变：
R version 3.2.1 (2015-06-18)
Platform: x86_64-pc-linux-gnu (64-bit)
Running under: Ubuntu precise (12.04.5 LTS)
locale:
[1] LC_CTYPE=en_IN LC_NUMERIC=C LC_TIME=en_IN
[4] LC_COLLATE=en_IN LC_MONETARY=en_IN LC_MESSAGES=en_IN
[7] LC_PAPER=en_IN LC_NAME=C LC_ADDRESS=C
[10] LC_TELEPHONE=C LC_MEASUREMENT=en_IN LC_IDENTIFICATION=C
attached base packages:
[1] stats graphics grDevices utils datasets methods base
other attached packages:
[1] flipTime_2.8.1 zoo_1.7-13
loaded via a namespace (and not attached):
[1] Rcpp_0.12.19 plotly_3.6.0 magrittr_1.5 munsell_0.5.0
[5] colorspace_1.3-2 lattice_0.20-33 R6_2.2.2 rlang_0.2.2
[9] stringr_1.3.1 httr_1.3.1 plyr_1.8.4 tools_3.2.1
[13] grid_3.2.1 gtable_0.2.0 htmltools_0.3.6 lazyeval_0.2.1
[17] digest_0.6.17 tibble_1.4.2 crayon_1.3.4 gridExtra_0.9.1
[21] purrr_0.2.5 tidyr_0.8.1 ggplot2_2.2.1 viridis_0.3.4
[25] base64enc_0.1-3 htmlwidgets_1.3 glue_1.3.0 memoise_1.0.0
[29] stringi_1.2.4 compiler_3.2.1 pillar_1.3.0 scales_1.0.0
[33] jsonlite_1.5 lubridate_1.3.3
将感谢您的帮助。
答案 0 :(得分：0)
您的代码对我有用。或者，尝试以下操作：
date <- "Jun 2009"
date <- paste("1", date) # Default day value
as.Date(date, format="%d %b %Y")
输出：
[1] "2009-06-01"
PS：如果字符串输入中缺少天，月或年之一，as.Date将给出NA作为输出，因此我们要添加默认的天值
希望这会有所帮助！