Question

# please note that I use ES6 syntax in JS.
# this: function() {...code here...}
# is the same as this: (()=> {...code here...});
# ES6 allows for shorthand annonymous functions

// wait for document to load
$(document).ready(()=> {
    // declare variable
    let foo = "hello world";
    // fetch data from the back end
    $.get("data.php?foo=" + encodeURIComponent(foo), (data)=> {
        # the $.get is the exact same as the AJAX code you used above but shorthanded
        // the 'data' is a parameter in the annonymous function that is storing the data from the back end
        console.log(data); // test that we are getting the data properly
        // remove table rows if they exist
        $("#mytable tbody").remove();
        $("#mytable").each(data, (i, item)=> {
            // add your data to the table by appending to the table
            # You would just continue this until you have all the cells you need filled. I'm going to skip to the end with adding the btn now
            $("#mytable").append('<tbody><tr><td>'+item.booking_email+'</td><td>'+item.booking_number+'</td><td><button class="btn btn-lg btn-danger deletebtn" id="'+item.booking_number+'">Delete</button></td></tbody>');
            /* the button has to have a unique ID to be called on so I assigned it the booking numbers to the ID. 
            Here's how we would call on it*/
            $(".deletebtn").unbind().click((d)=> {
                // you must unbind it first or you will have multiple events fire and you only want a single event to fire
                // pass the annonymous function a parameter (can be anything really I use d for delete)
                console.log(d.target.id); // check to make sure the button is getting an ID.
                // post to back end to delete then when it succeeds, we delete that row.
                $.post("data.php", {deletefoo: d.target.id}, (data)=> {
                    // delete row by calling on the target and removing the parent in this case being the row 'tr'
                    $(d.target).parents('tr').remove();
                });
            });
        });
        $("#mytable").show();
    });
});

尝试在终端上运行mongo时出现错误。我尝试重新安装并删除了锁定文件，然后重新启动了它，但仍然无法正常工作。我正在使用AWS，是否与AWS中网络设置的入站，出站有关，还是其他问题？

Answer 1

就像上面的评论一样，如果您尝试使用127.0.0.1连接到同一主机上的mongodb实例，则这是mongodb配置问题，因此，不可能是任何AWS安全规则。

因此，考虑到这是mongodb问题，请首先尝试使用以下命令在主机内部修复它：

sudo rm /var/lib/mongodb/mongod.lock
sudo mongod --repair
sudo service mongodb restart
sudo service mongod status

引用：https://stackoverflow.com/a/29083477/8407784

解决mongodb配置问题后，您需要测试来自另一台主机的连接，设置/etc/mongod.conf-bind_ip = 0.0.0.0（表示所有接口），仅用于测试

然后，您需要在主机实例上设置AWS安全规则，以允许外部实例在端口27017上访问它。

我无法连接到Ubuntu中的mongo db

1 个答案: